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3 years ago

1,498 divided by 30 equals blank

Mathematics

1 answer:

luda_lava [24]3 years ago

5 0

Answer:

49.333333 repeating.

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Help! im confuseddd!!!!!!!!!!

Assoli18 [71]

Answer:

sin B= square root of 3/ 2

Cos B= 1/2

tan B= square root of 3/1

Sin C=1/2

cos C square root of 3/2

tan C= 1/square root of 3

Step-by-step explanation:

4 0

2 years ago

Find gradient xe^y + 4 ln y = x² at (1, 1)

cricket20 [7]

$xe^y+4\ln y=x^2$

Differentiate both sides with respect to x, assuming y = y(x).

$\dfrac{\mathrm d(xe^y+4\ln y)}{\mathrm dx}=\dfrac{\mathrm d(x^2)}{\mathrm dx}$

$\dfrac{\mathrm d(xe^y)}{\mathrm dx}+\dfrac{\mathrm d(4\ln y)}{\mathrm dx}=2x$

$\dfrac{\mathrm d(x)}{\mathrm dx}e^y+x\dfrac{\mathrm d(e^y)}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x$

$e^y+xe^y\dfrac{\mathrm dy}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x$

Solve for dy/dx :

$e^y+\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x$

$\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x-e^y$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x-e^y}{xe^y+\frac4y}$

If y ≠ 0, we can write

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2xy-ye^y}{xye^y+4}$

At the point (1, 1), the derivative is

$\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=1,y=1}=\boxed{\dfrac{2-e}{e+4}}$

4 0

3 years ago

If the angle NME = x+97, the angle EML = x+66, and the angle NML = 141, find the angle EML

defon

Answer:

∠ EML = 94°

Step-by-step explanation:

See the attached diagram.

The three angles ∠ NME, ∠ EML and ∠ NML together make 360°.

Now, ∠ NME = x + 97, ∠ EML = x + 66 and ∠ NML = 141°

Hence, (x + 97) + ( x + 66) + 141 = 360

⇒ 2x + 304 = 360

⇒ 2x = 56

⇒ x = 28

So, ∠ EML = x + 66 = 28 + 66 = 94° (Answer)

6 0

3 years ago

If s and t are integers greater than 1 and each is a factor of the integer n, which of the following must be a factor of n^{st}

andrey2020 [161]

Answer:

E) 1 and 2

Step-by-step explanation:

We are given that there are two integers (s and t) and they are factors of another integer (n). For example if s = 3 and t = 2, we can have n = 6.

Thus:

n^(st) = 6^(2*3) = 6^6 = (2^6)(3^6)

For the first condition: s^t = 3^2 is a factor of (2^6)(3^6)

For the second condition: (st)^2 = (3*2)^2 = 6^2 is a factor of 6^6

For the third condition: s+t = 3+2 = 5 is not a factor of 6^6 or (2^6)(3^6)

Therefore, only 1 and 2 are factors of n^(st)

6 0

3 years ago

Read 2 more answers

. <img src="https://tex.z-dn.net/?f=lim%20%5Cfrac%7B%20%5Ctan%28ax%20-%20a%29%20%2B%20b%20-%202%20%7D%7Bx%20-%201%7D%20" id=

navik [9.2K]

Answer:

i dont know

Step-by-step explanation:

6 0

2 years ago