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pashok25 [27]
3 years ago
11

Find the Mean and MAD of the data set: 7, 6, 17, 8, 7, 9

Mathematics
2 answers:
Oliga [24]3 years ago
7 0

Answer:

Mean:9

MAD:2.7

Step-by-step explanation:

Mean:7+6+17+8+7+9=<u>54/6</u>=9

MAD: 9-6.3=2.7

(6.3 is the mean absolute deviation)

matrenka [14]3 years ago
5 0

Answer: Mean: 9

MAD: 46

Step-by-step explanation:

I will show u how to work out the mean

and the mad so u know

MEAN:

The mean is the average of the numbers. It is easy to calculate: add up all the numbers, then divide by how many numbers there are. In other words it is the sum divided by the count.

MAD:

1) To find the mean absolute deviation of the data, start by finding the mean of the data set.

2 )Find the sum of the data values, and divide the sum by the number of data values.

3) Find the absolute value of the difference between each data value and the mean: |data value – mean.

MARK THIS AS THE BRAINLIEST PLEASE

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Identify the slope of the line for the equation y = 10x + 3.
Iteru [2.4K]

Answer:324

Step-by-step explanation:

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Podcza

7 0
3 years ago
What is the probability that more than twelve loads occur during a 4-year period? (Round your answer to three decimal places.)
Nataly_w [17]

Answer:

Given that an article suggests

that a Poisson process can be used to represent the occurrence of

structural loads over time. Suppose the mean time between occurrences of

loads is 0.4 year. a). How many loads can be expected to occur during a 4-year period? b). What is the probability that more than 11 loads occur during a

4-year period? c). How long must a time period be so that the probability of no loads

occurring during that period is at most 0.3?Part A:The number of loads that can be expected to occur during a 4-year period is given by:Part B:The expected value of the number of loads to occur during the 4-year period is 10 loads.This means that the mean is 10.The probability of a poisson distribution is given by where: k = 0, 1, 2, . . ., 11 and λ = 10.The probability that more than 11 loads occur during a

4-year period is given by:1 - [P(k = 0) + P(k = 1) + P(k = 2) + . . . + P(k = 11)]= 1 - [0.000045 + 0.000454 + 0.002270 + 0.007567 + 0.018917 + 0.037833 + 0.063055 + 0.090079 + 0.112599 + 0.125110+ 0.125110 + 0.113736]= 1 - 0.571665 = 0.428335 Therefore, the probability that more than eleven loads occur during a 4-year period is 0.4283Part C:The time period that must be so that the probability of no loads occurring during that period is at most 0.3 is obtained from the equation:Therefore, the time period that must be so that the probability of no loads

occurring during that period is at most 0.3 is given by: 3.3 years

Step-by-step explanation:

8 0
3 years ago
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