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Evgesh-ka [11]
2 years ago
10

Solve the following quadratic equations using factoring. C. X^2-10=9x

Mathematics
1 answer:
boyakko [2]2 years ago
8 0

we can easily solve this one by splitting theiddle term

x2 - 9x -10

x2 -10x + x - 10

x(x - 10) 1( x - 10)

(x + 1) (x-10)

x = -1 or 10

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May u guys help me jus me out 5 ez questions for u guys to help me with
Elena-2011 [213]

Answer:

1. -29/156 2. 38/45 3. 29/45 4. 113/24 or about 4.7 5. 457/1,  914/2,  1371/3

Step-by-step explanation:

3/13 - 5/12 can be simplified to 36/156 - 65/156. Subtract this and you get -29/156  

4/9 + 2/5 can be simplified to 20/45 + 18/45. Add this and you get

38/45

5/8 - 2/9  can be simplified to 45/72 - 16/72. Subtract this and you get

29/45

3 1/2 + 2 5/12 can be first made irrational to 7/2 + 29/24. This can be simplified to 84/24 + 29/24

113/24 or about 4.7

Not sure about the 457, but to convert it, you multiply it by whatever denominator you have. For example

1x457 = 457/1

2x457 = 914/2

And finally 3x457 = 1371/3

3 0
2 years ago
All vectors are in Rn. Check the true statements below:
Oduvanchick [21]

Answer:

A), B) and D) are true

Step-by-step explanation:

A) We can prove it as follows:

Proy_{cv}y=\frac{(y\cdot cv)}{||cv||^2}cv=\frac{c(y\cdot v)}{c^2||v||^2}cv=\frac{(y\cdot v)}{||v||^2}v=Proy_{v}y

B) When you compute the product Ax, the i-th component is the matrix of the i-th column of A with x, denote this by Ai x. Then, we have that ||Ax||=\sqrt{(A_1 x)^2+\cdots (A_n x)^2}. Now, the colums of A are orthonormal so we have that (Ai x)^2=x_i^2. Then ||Ax||=\sqrt{(x_1)^2+\cdots (x_n)^2}=||x||.

C) Consider S=\{(0,2),(2,0)\}\subseteq \mathbb{R}^2. This set is orthogonal because (0,2)\cdot(2,0)=0(2)+2(0)=0, but S is not orthonormal because the norm of (0,2) is 2≠1.

D) Let A be an orthogonal matrix in \mathbb{R}^n. Then the columns of A form an orthonormal set. We have that A^{-1}=A^t. To see this, note than the component b_{ij} of the product A^t A is the dot product of the i-th row of A^t and the jth row of A. But the i-th row of A^t is equal to the i-th column of A. If i≠j, this product is equal to 0 (orthogonality) and if i=j this product is equal to 1 (the columns are unit vectors), then A^t A=I    

E) Consider S={e_1,0}. S is orthogonal but is not linearly independent, because 0∈S.

In fact, every orthogonal set in R^n without zero vectors is linearly independent. Take a orthogonal set \{u_1,u_2\cdots u_p\} and suppose that there are coefficients a_i such that a_1u_1+a_2u_2\cdots a_nu_n=0. For any i, take the dot product with u_i in both sides of the equation. All product are zero except u_i·u_i=||u_i||. Then a_i||u_i||=0 then a_i=0.  

5 0
3 years ago
What percent of 3000 is 18??
77julia77 [94]
To solve this problem you have to set up a proportion. To form one side of the proportion you use "is over of" meaning what number represented by is, in this case 18, is placed over the number represented by of, 3000. \frac{18}{3000} Since you are finding the percent of something, youre x value is placed above "100" because percent values are most commonly out of 100%. \frac{x}{100} 
So now your proportion will look like \frac{18}{3000}\frac{x}{100} To solve the proportion you cross multiply and divide. So you multiply 100 and 18 since they are crossed from each other, then divide 1800 by 3000. The answer is .6. 18 is .6% of 3000. 
5 0
3 years ago
HELP............................................................................................................................
weqwewe [10]

Answer:

More than half I think its based off of a 1-10% scale

Step-by-step explanation:

it's greater than 5%

7 0
3 years ago
melania walked her dog 2 1 /5 miles. cqthy walked her dog 1 3/4 times as far as melania did. how many more miles did cathy walk
stira [4]
Let’s set this equation up to make this easier.

melanie= 2 1/5 miles walked
cathy= 1 3/4 more times than melanie.

when an equation says the word, more than this means adding. when it says less than this means subtraction. when it says times (in this question) then multiply.

so, if cathy walked 1 3/4 more times than melanie what we would do is multiply 1 3/4 to what melanie was walking. so 2 1/5 times 1 3/4 which equals 3.85.

so overall, cathy walked 3.85 more miles than melanie.
7 0
3 years ago
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