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charle [14.2K]
3 years ago
12

When given a radical to simplify, if no number appears in the index location then it is a one.

Mathematics
1 answer:
slamgirl [31]3 years ago
6 0

Answer:

that is false! im pretty sure!

let me know if u need any more help cutie!

Step-by-step explanation:

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Vera_Pavlovna [14]
A is -11
Is that what you're trying to find
7 0
3 years ago
Read 2 more answers
Simplify this equation 7x+3x-10
DerKrebs [107]
<span>Simplify this equation 7x+3x-10:

</span><span>7x + 3x - 10 = 10x - 10

<u>Hope his answer helps you!!!</u>
</span>
<em>Ps: Please mark Brainliest so I can Rank up higher! I'm almost there!!</em>

7 0
3 years ago
|x|-2≤3<br>|x+1| +5&lt;7 how do I shove this
Fofino [41]

3. <  \leqslant  {?}^{2}
6 0
3 years ago
Un<br> How many solutions does this system have?<br> 12x-4y=-8<br> y=3x+2
Talja [164]

Answer:

Infinite

Step-by-step explanation:

Get both in the form y = first.

12x - 4y = -8

-4y = -8 - 12x

y = 2 + 3x

y = 3x + 2

These are the same line so all points are the same so that means there are infinite answers.

If ONLY the number in front of the x was the same there would be 0 answers, they would be parallel lines, and if the number in front of the xs were different there would only be one answer.  

3 0
2 years ago
Expand using the properties and rules for logarithms
malfutka [58]

Consider expression \log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right).

1. Use property

\log_a\dfrac{b}{c}=\log_ab-\log_ac.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2.

2. Use property

\log_abc=\log_ab+\log_ac.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2.

3. Use property

\log_ab^k=k\log_ab.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2.

4. Use property

\log_{a^k}b=\dfrac{1}{k}\log_ab.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{2^{-1}}2=\\ \\=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+\log_22=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+1.

Answer: correct option is B.

7 0
3 years ago
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