Answer:
uh, I am 12 but I will try my best to answer your question :D
It depends if you trust the person for what they said, not sure exactly all this is, but I think if it's a private university, then it would be called a "boost"
Step-by-step explanation:
Can I have brainiest please? I mean, I did try my best to answer your question for being 12 years of age! I hope this helped you! Have a wonderful day! God bless!
Answer:
0.6666666666666666... cups
Step-by-step explanation:
the six is endless
Answer:
DM should equal 20 inches
You have a 3 out of 6 chance of landing on a , or a 3
Answer:
The 95% confidence interval for the true population mean of pollutant discharge is (26.7 tons, 33.7 tons).
Step-by-step explanation:
Let <em>X</em> represent the daily level of pollutant discharge in the manufacturing district in Pittsburgh.
The monitoring equipment reveals that for the 28 days of the February month
Mean daily discharge per factory, (
) = 30.2 tons
Standard deviation daily discharge per factory, (<em>s</em>) = 9.1 tons
Compute the critical value of <em>t</em> for 95% level of confidence and (n - 1 =) 27 degrees of freedom as follows:
![t_{0.05/2, 27}=2.052](https://tex.z-dn.net/?f=t_%7B0.05%2F2%2C%2027%7D%3D2.052)
*Use a t-table.
Compute the 95% confidence interval for the true population mean of pollutant discharge as follows:
![CI=\bar x\pm t_{\alpha/2, (n-1)}\cdot\frac{s}{\sqrt{n}}](https://tex.z-dn.net/?f=CI%3D%5Cbar%20x%5Cpm%20t_%7B%5Calpha%2F2%2C%20%28n-1%29%7D%5Ccdot%5Cfrac%7Bs%7D%7B%5Csqrt%7Bn%7D%7D)
![=30.2\pm 2.052\times\frac{9.1}{\sqrt{28}}\\\\=30.2\pm 3.53\\\\=(26.67, 33.73)\\\\\approx (26.7, 33.7)](https://tex.z-dn.net/?f=%3D30.2%5Cpm%202.052%5Ctimes%5Cfrac%7B9.1%7D%7B%5Csqrt%7B28%7D%7D%5C%5C%5C%5C%3D30.2%5Cpm%203.53%5C%5C%5C%5C%3D%2826.67%2C%2033.73%29%5C%5C%5C%5C%5Capprox%20%2826.7%2C%2033.7%29)
Thus, the 95% confidence interval for the true population mean of pollutant discharge is (26.7 tons, 33.7 tons).