All categories

3 years ago

Find the zeros for y=x^2-3x-10

Mathematics

2 answers:

attashe74 [19]3 years ago

7 0

Answer:

x=5 and -2

Step-by-step explanation:

Deffense [45]3 years ago

3 0

Answer: y=x^2-3x-10 = The solution is the result of

−

and

You might be interested in

This is hard so i put more points and uhm this is stupid -w-

MAVERICK [17]

Answer:

The mean is the average of the numbers. It is easy to calculate: add up all the numbers, then divide by how many numbers there are.

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What is the answer?

Dimas [21]

Answer:

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Question 5(Multiple Choice Worth 1 points) (03.03 LC) If a figure has been dilated by a scale factor of 4, which statement expla

Novosadov [1.4K]

Answer:

A translation can map one angle unto another since dilations preserve angle measures of triangles

Step-by-step explanation:

The dilation of the figure by a scale factor of 4 gives an image that is 4 times the size of the original figure. However, the interior angles of the image and the original figure remain the same

A translation is a rigid transformation, such that the image and the preimage of a translation transformation have the same dimensions and angles

A translation of three consecutive non-linear points of the dilated image to the vertex and the two lines joining the corresponding point on the image, translates the angle at the given vertex

The above process can be repeated, to translate a second angle from the image to the preimage, from which it can be shown that the two figures are similar using Angle Angle, AA, similarity postulate

8 0

3 years ago

. A right cylindrical drum is to hold 7.35 cubic feet of liquid. Find the dimensions (radius of the base and height) of the drum

Drupady [299]

Answer:

$r=1.05\ \text{ft}$

$h=2.12\ \text{ft}$

$20.91\ \text{ft}^3$

Step-by-step explanation:

r = Radius

h = Height

Volume of cylinder = $7.35\ \text{ft}^3$

$V=\pi r^2h\\\Rightarrow h=\dfrac{V}{\pi r^2}\\\Rightarrow h=\dfrac{7.35}{\pi r^2}$

Surface area is given by

$A=2\pi r^2+2\pi rh\\\Rightarrow A=2\pi r^2+2\pi r\dfrac{7.35}{\pi r^2}\\\Rightarrow A=2\pi r^2+\dfrac{14.7}{r}$

Differentiating with respect to radius we get

$\dfrac{dA}{dr}=4\pi r-\dfrac{14.7}{r^2}$

Equating with zero we get

$0=4\pi r-\dfrac{14.7}{r^2}\\\Rightarrow 4\pi r=\dfrac{14.7}{r^2}\\\Rightarrow r^3=\dfrac{14.7}{4\pi}\\\Rightarrow r=(\dfrac{14.7}{4\pi})^{\dfrac{1}{3}}\\\Rightarrow r=1.05$

$\dfrac{d^2A}{dr^2}=4\pi-2\times \dfrac{14.7}{r^3}\\\Rightarrow \dfrac{d^2A}{dr^2}=4\pi+2\times \dfrac{14.7}{1.05^3}\\\Rightarrow \dfrac{d^2A}{dr^2}=37.96>0$