Answer:
Because -3-/8 itself is an irrational number. No matter the operation it wil always be irrational
Step-by-step explanation:
Answer:
whats the question
Step-by-step explanation:
Answer:
![\boxed{\math{\frac{1}{9}\text{ lb}}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cmath%7B%5Cfrac%7B1%7D%7B9%7D%5Ctext%7B%20lb%7D%7D%7D)
Step-by-step explanation:
![\text{Size of one serving} = \dfrac{\text{Total size}}{\text{No of servings}} = \dfrac{\frac{2}{3}\text{ lb}}{\text{6 servings}}\\\\\text{Change the 6 to a fraction and change divide to multiply}\\\\\dfrac{2}{3} \div 6 = \dfrac{2}{3} \times \dfrac{1}{6}](https://tex.z-dn.net/?f=%5Ctext%7BSize%20of%20one%20serving%7D%20%3D%20%5Cdfrac%7B%5Ctext%7BTotal%20size%7D%7D%7B%5Ctext%7BNo%20of%20servings%7D%7D%20%3D%20%5Cdfrac%7B%5Cfrac%7B2%7D%7B3%7D%5Ctext%7B%20lb%7D%7D%7B%5Ctext%7B6%20servings%7D%7D%5C%5C%5C%5C%5Ctext%7BChange%20the%206%20to%20a%20fraction%20and%20change%20divide%20to%20multiply%7D%5C%5C%5C%5C%5Cdfrac%7B2%7D%7B3%7D%20%5Cdiv%206%20%3D%20%5Cdfrac%7B2%7D%7B3%7D%20%5Ctimes%20%5Cdfrac%7B1%7D%7B6%7D)
![\text{Cancel the 2s}\\\\\dfrac{2}{3} \times \dfrac{1}{6} = \dfrac{1}{3} \times \dfrac{1}{3}\\\\\text{Multiply numerators and denominators}\\\\\dfrac{1}{3} \times \dfrac{1}{3} = \dfrac{1}{9}\\\\\text{Each serving contains }\boxed{\mathbf{\frac{1}{9}\textbf{ lb}}}](https://tex.z-dn.net/?f=%5Ctext%7BCancel%20the%202s%7D%5C%5C%5C%5C%5Cdfrac%7B2%7D%7B3%7D%20%5Ctimes%20%5Cdfrac%7B1%7D%7B6%7D%20%3D%20%5Cdfrac%7B1%7D%7B3%7D%20%5Ctimes%20%5Cdfrac%7B1%7D%7B3%7D%5C%5C%5C%5C%5Ctext%7BMultiply%20numerators%20and%20denominators%7D%5C%5C%5C%5C%5Cdfrac%7B1%7D%7B3%7D%20%5Ctimes%20%5Cdfrac%7B1%7D%7B3%7D%20%3D%20%5Cdfrac%7B1%7D%7B9%7D%5C%5C%5C%5C%5Ctext%7BEach%20serving%20contains%20%7D%5Cboxed%7B%5Cmathbf%7B%5Cfrac%7B1%7D%7B9%7D%5Ctextbf%7B%20lb%7D%7D%7D)
Answer:
Area = 36 ![inches ^ 2](https://tex.z-dn.net/?f=inches%20%5E%202)
Step-by-step explanation:
There must be an error with the statement, because it is strange that the length of the frame is equal to its thickness.
Assuming that the data supplied is correct, we can do the following procedure.
Let's call L the length of the frame.
We know how much each side of the square measures.
L = 3 inches
We also know that the thickness (s) is:
s = 3 inches.
Then the area of the frame is equal to:
Area = Perimeter * thickness
Area = 4L*s
Area = 3*4*3
Area = 36 ![inches ^ 2](https://tex.z-dn.net/?f=inches%20%5E%202)