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ValentinkaMS [17]
3 years ago
14

Help I would love to give you a thanks

Mathematics
2 answers:
WARRIOR [948]3 years ago
7 0

Answer:

Formula

Step-by-step explanation:

nignag [31]3 years ago
5 0

Answer:

formula because it gives you the number and tells you what to do.

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(3x-5)/(x-5)&gt;=0 <br> How do I get the answers for this problem?
Diano4ka-milaya [45]
\frac{3x-5}{x-5} > 0 

First, note that x is undefined at 5. / x ≠ 5
Second, replace the inequality sign with an equal sign so that we can solve it like a normal equation. / Your problem should look like: \frac{3x-5}{x-5} = 0
Third, multiply both sides by x - 5. / Your problem should look like: 3x - 5 = 0
Forth, add 5 to both sides. / Your problem should look like: 3x = 5
Fifth, divide both sides by 3. / Your problem should look like: x = \frac{5}{3}
Sixth, from the values of x above, we have these 3 intervals to test: 
x < \frac{5}{3}
\frac{5}{3} < x < 5
x > 5
Seventh, pick a test point for each interval. 

1. For the interval x < \frac{5}{3} :
Let's pick x - 0. Then, \frac{3x0-5}{0-5} > 0
After simplifying, we get 1 > 0 which is true.
Keep this interval.

2. For the interval \frac{5}{3} < x < 5:
Let's pick x = 2. Then, \frac{3x2-5}{2-5} > 0
After simplifying, we get -0.3333 > 0, which is false.
Drop this interval.

3. For the interval x > 5:
Let's pick x = 6. Then, \frac{3x6-5}{6-5} > 0
After simplifying, we get 13 > 0, which is ture.
Keep this interval.
Eighth, therefore, x < \frac{5}{3} and x > 5

Answer: x < \frac{5}{3} and x > 5

3 0
3 years ago
find three numbers whose sum is 32 if the second is 1 more than the first and the first is 4 less than the third
Alex777 [14]
X+y+z=32
x=z-4
y=x+1
z=x+4
x+x+1+x+4=32
3x+5=32
3x=27
x=9
y=10
z=13

Hope this helps :)
7 0
3 years ago
Which value equivalent to (f•g)(10)?
Anna35 [415]

Answer:wha

Step-by-step explanation:

5 0
2 years ago
Solve for x.
olga nikolaevna [1]

Step-by-step explanation:

4.6 -.75 =

? \3 \frac{7}{20}

so x <3 7/20

3 0
2 years ago
State the domain and range of f(x)=[[x-2]]
noname [10]

Answer:

domain: -infinity < x <infinity or (-infinity, infinity)

range: -infinity < f(x) < infinity or (-infinity, infinity)

Step-by-step explanation:

8 0
3 years ago
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