All categories

3 years ago

Q. # 15 please help to solve

Mathematics

1 answer:

navik [9.2K]3 years ago

5 0

Since
$18x^3=2\cdot 3\cdot 3\cdot x\cdot x\cdot x \\ \\ 30x^5=2\cdot 3\cdot 5\cdot x\cdot x\cdot x\cdot x\cdot x$
you can see that common expression is
$2\cdot 3\cdot x\cdot x\cdot x=6x^3$ .
Answer: Correct choice is A.

You might be interested in

Task 1:Different ways to represent Relations. Complete the table with the different ways.. Complete the table with the different

rewona [7]

Domains are the first sets of numbers they are also the x and the range is the second sets of number and is the y

8 0

2 years ago

Which of the following has no solution?

Luba_88 [7]

Answer:

see below

Step-by-step explanation:

Option 1: the two solution sets overlap at <em>x=1</em>.

Option 2: the two solution sets do not overlap; no solution.

Option 3: together, the two set describe <em>all real numbers</em>.

5 0

3 years ago

What is the product of (4x)(-3x^8)(-7x^3)

Semenov [28]

(4x)(-3x^8)(-7x^3)

4 (-3)(-7) = 84

x(-x^8)(-x^3) = x^(1 + 8 + 3) = x^12

Answer: 84x^12

4 0

3 years ago

Q1.

lisov135 [29]

The answer is 0.49 because u jus add it all and minus it from 1

3 0

3 years ago

Read 2 more answers

Assume that a consumer has a given budget or income of $12, and that she can buy only two goods, apples or bananas. The price of

expeople1 [14]

Answer:

The consumer will either be able to buy 8 apples or 16 bananas with a budget of $12.

Step-by-step explanation:

We are given the following in the question:

Total budget or income = $12

Cost of an apple = $1.50

Cost of a banana = $0.75

The consumer spent all of her budget on just apples or just bananas.

Number of apples purchased =

$=\displaystyle\frac{\text{Total budget}}{\text{Cost of an apple}} = \frac{12}{1.50} = 8$

Numbers of banana purchased =

$=\displaystyle\frac{\text{Total budget}}{\text{Cost of a banana}} = \frac{12}{0.75} = 16$

Thus, the consumer will either be able to buy 8 apples or 16 bananas with a budget of $12.

8 0

3 years ago