F(x) = 1/(x+2) & g(x) = x/(x-3)
(f(x) + g(x) = 1/(x+2) + x/(x-3). Reduce to same denominator:
1/(x+2) + x/(x-3) =(x-3) + x(x-3)/(x+2).(x-3) ==> (x²+3x-3)/(x+2).(x-3)
There are 11 ways a pair of dice can show a 5. Of those, 2 have a sum of 6.
Your probability is 2/11.
I’m not quite sure what the question is, but 81 cookies distributed among 44 people would mean that each person gets 0.02 cookies each.
