Answer:
Domain: {x | x is all real numbers} Range: {y | y ≥ 6}
Step-by-step explanation:
Domain is the set of all x values. No operations restrict the domain in this case. The domain is all real numbers.
Range is the set of all y values. Absolute value has a v shape starting at 0. Adding 6 raises this vertex to 6. The range is therefore all numbers greater than or equal to 6.
2)
A: 5
B: 9a & a (from a/6)
C: -5 & ÷4
D: -5 & 9a
I haven't done algebra in a year, so don't think my answers are perfect!
definitions:
term: something separated by a sign/symbol (÷, ×, - +) (a/6 are two separate terms, ÷)
constant terms: variables that can be solved.
unlike terms: terms that don't "go" together, you can't subtract 5 from 9a because there's a variable in the way (eyy that rhymes)
like terms: terms that you can add/subtract/multiply/divide to another term
(another answer to c is 9a & a)
Answer:
x = (-5 ± 2√10) / 3
Step-by-step explanation:
5 − 10x − 3x² = 0
Write in standard form:
-3x² − 10x + 5 = 0
Solve with quadratic formula:
x = [ -b ± √(b² − 4ac) ] / 2a
x = [ -(-10) ± √((-10)² − 4(-3)(5)) ] / 2(-3)
x = [ 10 ± √(100 + 60) ] / -6
x = (10 ± 4√10) / -6
x = (-5 ± 2√10) / 3
The answer is c trust me it is c trust me the answer is c just trust me it is c
Step-by-step explanation:
<h3>
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Prove the LHS
Using trigonometric identities
That's
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<u>Rewrite the expression</u>
We have
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So we have
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Using trigonometric identities
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<u>Rewrite the expression</u>
That's
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Reduce the expression with cos a
We have the final answer as
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As proven
Hope this helps you
