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Rasek [7]
2 years ago
11

Consider the proof for the identity csc(x)+sin(x)=(2-cos^(2)(x))/(sin(x)).

Mathematics
1 answer:
spin [16.1K]2 years ago
8 0

1. given:

csc(x) + sin(x)

2. definition of csc(x) :

1/sin(x) + sin(x)

3. combining fractions with a common denominator:

(1 + sin²(x))/sin(x)

4. expanding 1 = cos²(x) + sin²(x) :

(cos²(x) + sin²(x) + sin²(x))/sin(x)

5. simplifying:

(2 sin²(x) + cos²(x))/sin(x)

6. employing the same identity as in (4) :

(2 (1 - cos²(x)) + cos²(x))/sin(x)

7. expanding 2 (1 - cos²(x)) :

(2 - 2 cos²(x) + cos²(x))/sin(x)

8. simplifying:

(2 - cos²(x))/sin(x)

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Solution of the equation: x=6\frac{1}{2}

Step-by-step explanation:

The equation that we have to solve in this problem is:

13\frac{3}{4}+x=7\frac{1}{4}

The first step to do is to rewrite the mixed fractions as improper fractions. We have:

13\frac{3}{4}=\frac{13\cdot 4+3}{4}=\frac{52+3}{4}=\frac{55}{4}

And

7\frac{1}{4}=\frac{7\cdot 4+1}{4}=\frac{29}{4}

So the equation becomes

\frac{29}{4}+x=\frac{55}{4}

Now we multiply by 4 each term on both sides, and we get

29+4x=55

Now we subtract 29 from both sides,

4x=55-29=26

And finally, we divide both sides by 4:

x=\frac{26}{4}=\frac{13}{2}=6\frac{1}{2}

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B: billie's solution is incorrect since she didnt  

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