<h3>The volume of a container with a radius of 4 centimeters and a height of 4 centimeters is 67.2 cubic centimeter</h3>
<em><u>Solution:</u></em>
<em><u>The volume of a container varies jointly with the square of its radius, r, and its height, h</u></em>
Therefore,
<em><u>The container has a height of 10 centimeters, and radius of 6 centimeters, and a volume of 377 cubic centimeters</u></em>
Substitute v = 377 and h = 10 and r = 6 in eqn 1
<em><u>What is the volume of a container with a radius of 4 centimeters and a height of 4 centimeters?</u></em>
Substitute k = 1.05 and r = 4 and h = 4 in eqn 1
Thus volume of a container with a radius of 4 centimeters and a height of 4 centimeters is 67.2 cubic centimeter
Answer:
percentage of 0.9% of 1,000
You have posted 2 separate questions here. Please, next time, separate them with a blank line:
<span>A circle has an area of 81 3.14 units . what is the diameter in terms of 3.14?
I'd prefer you write this as
"</span><span>A circle has an area of 81 pi units . what is the diameter in terms of pi?
Area of a circle = A = pi*r^2. Note that r= diameter / 2. Here, the area is 81 pi square units, or 9^2 * pi square units, which means that the radius is 9 units. The diameter is then 2(9 units) = 18 units.
Your second question, separated from the first, is:
"</span><span>a circle has an area of 81 Pi square units what is the diameter of the circle?"
</span><span>
Use the following formula or formulas: d = 2*r; A = pi*r^2; A = pi*(d/2)^2. Find r first, and then find d.
</span>
Answer:
The answer is D.. 2^0
Step-by-step explanation:
i had the same question in my program
Part (a)
Use the slope formula to compute the slope from x = 4 to x = 6
So effectively we're finding the slope of the line through (4,70) and (6,68)
We get the following
m = (y2-y1)/(x2-x1)
m = (68-70)/(6-4)
m = -2/2
m = -1
Repeat for the points that correspond to x = 6 and x = 8
m = (y2-y1)/(x2-x1)
m = (73-68)/(8-6)
m = 5/2
m = 2.5
Now average the two slope values
We'll add up the results and divide by 2
(-1+2.5)/2 = 1.5/2 = 0.75
The estimate of T'(6) is 0.75
This works because T'(x) measures the slope of the tangent line on the T(x) curve. Averaging the secant slopes near x = 6 will help give us an estimate of T'(6), which is the slope of the tangent at x = 6 on T(x).
<h3>Answer: 0.75</h3>
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Part (b)
The value T'(6) = 0.75 represents the instantaneous rate of change of the temperature per hour.
More specifically, T'(6) = 0.75 means the temperature is increasing by an estimated 0.75 degrees per hour at the exact instant of x = 6 hours. This instantaneous rate of change is like a snapshot at this very moment in time; in contrast, the slope formula results we computed above measure the average rate of change between the endpoints mentioned.