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telo118 [61]
3 years ago
5

S squared minus y cubed

Mathematics
1 answer:
mash [69]3 years ago
8 0

Answer:

s^2 - y^3 ........

Step-by-step explanation:

s^2 - y^3

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tigry1 [53]
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3 years ago
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Find the maxmium area of a rectangular plot of land which can be enclosed by rope of length 60 metres​
mario62 [17]

Answer:

225 m²

Step-by-step explanation:

If W is the width of the rectangle, and L is the length, then:

60 = 2W + 2L

A = WL

Use the first equation to solve for one of the variables:

30 = W + L

L = 30 − W

Substitute into the second equation:

A = W (30 − W)

A = 30W − W²

This is a parabola, so we can find the vertex using the formula x = -b/(2a).

W = -30 / (2 × -1)

W = 15

Or, we can use calculus:

dA/dW = 30 − 2W

0 = 30 − 2W

W = 15

Solving for L:

L = 30 − W

L = 15

So the maximum area is:

A = WL

A = (15)(15)

A = 225

3 0
3 years ago
Solve the following linear equation for k.<br> 2 (k-5) + 3k = k + 6
kiruha [24]

Answer:

2(k-5)+3k=k+6

-3k. -3k

2(k-5)=-2k+6

/2. /2

k-5=-k+3

+k. +k

2k-5=3

+5. +5

2k=8

/2. /2

k=4

7 0
3 years ago
The perimeter of a rectangle is 26 cm. The rectangle has a length of 8 cm. What is the width of the rectangle?
zvonat [6]

Answer:

A. 2(8)+2(w)=26

B. 16+2w=26

Subtract 16 from both sides of the equation

2w=10

Divide both side by 2

The width is 5

Step-by-step explanation:

3 0
3 years ago
Can someone please help me find the surface area of C before 8:30?!
avanturin [10]
There are some area calculators on google if you need but I will try work it out..... if I don’t know I won’t send another answer
4 0
3 years ago
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