Jozy throws a stone off of a bridge into a river. The function fff models the stone's height (in meters) above the water as a fu
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a. The percentage of the circle occupied by the hexagon is 82.7%
b. The percentage of the circle not occupied by the hexagon is 17.3%
Step-by-step explanation:
a regular hexagon inscribed in a circle is approximately 0.827 times the
area of that same circle
1. Assume that area the circle is x
2. Find the ratio of area hexagon to area circle
3. Change The ratio to percentage
4. Subtract area hexagon from area circle to find the area not occupied
by the hexagon and do the same steps 2 and 3 with the area not
occupied and the circle
∵ The regular hexagon inscribed in a circle
∴ Area the circle > area of the hexagon
∵ Area the circle is x
∵ Area the hexagon is 0.827 times the area of the circle
∴ Area hexagon = 0.827(x)
∵ The ratio between area hexagon and area circle =
- Cancel x up with x down
∴ The ratio between area hexagon and area circle = 0.872
- Change the ratio to percentage by multiply it by 100%
∴ The percentage of area hexagon to area circle = 0.827 × 100%
∴ The percentage of area hexagon to area circle = 82.7%
a. The percentage of the circle occupied by the hexagon is 82.7%
∵ Area the circle is x
∵ Area the hexagon is 0.827 x
∴ The area not occupied by the hexagon = x - 0.827 x
∴ The area not occupied by the hexagon = 0.173 x
The ratio between area not occupied by the hexagon and area circle
=
- Cancel x up with x down
∴ The ratio between area not occupied by the hexagon and area
circle = 0.173
- Change the ratio to percentage by multiply it by 100%
∴ The percentage of area not occupied by the hexagon to area
circle = 0.173 × 100%
∴ The percentage of area not occupied by the hexagon to area
circle = 17.3%
b. The percentage of the circle not occupied by the hexagon is 17.3%
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Kinetic energy formula is
K.E =
mv²
m = 0.5 kg
v = 3 m/s
Plug in the given.
K.E = × (0.5) × (3)²
= 2.25 J
K.E =
m = 0.5 kg
v = 3 m/s
Plug in the given.
K.E =
= 2.25 J