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Damm [24]
3 years ago
10

Which conjecture is possible to prove is congruent? A. All quadrilaterals with 4 equal angles B. All triangles with 3 equal angl

es C. All quadrilaterals with 4 equal sides D. All triangles with 3 equal sides
Mathematics
1 answer:
igor_vitrenko [27]3 years ago
7 0

Answer:  D. All triangles with 3 equal sides

Step-by-step explanation:

Remember, congruence means that the sides are equal and also the corresponding angles:

A) Quadrilaterals with 4 equal angles.

Here we can have, for example, a lot of different rectangles and squares, because all of them have only 45° angles, but a square is not congruent with a rectangle, so this option is not correct.

B) Triangles with 3 equal angles.

Think in the triangles, the 3 angles are 60°,

But we can craft this angle with a lot of different side lengths, so this is not the correct option, so not all the triangles with equal angles are congruent, then this option is incorrect.

C) Quadrilaterals with 4 equal sides: Here we can have a square, or a rhombus, or a parallelogram, so this option is also incorrect.

D) Triangles with 3 equal sides:

Now, we have the set of all the triangles where the length of the 3 sides is the same.

Now, if you have 3 knowed lenghts (the ones shared by the set of triangles) you can only create one triangle with them, this is known as the SSS criterion of congruence for triangles. This is the correct option.

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Step-by-step explanation:

Let x represent the number of days it will take the cost of hiring either actor A or actor B to be the same.

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A statistics instructor who teaches a lecture section of 160 students wants to determine whether students have more difficulty w
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Answer:

There is no evidence that there is no significant difference between the sample means

Step-by-step explanation:

given that a  statistics instructor who teaches a lecture section of 160 students wants to determine whether students have more difficulty with one-tailed hypothesis tests or with two-tailed hypothesis tests. On the next exam, 80 of the students, chosen at random, get a version of the exam with a 10-point question that requires a one-tailed test. The other 80 students get a question that is identical except that it requires a two-tailed test. The one-tailed students average 7.81 points, and their standard deviation is 1.06 points

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Mean 7.8100 7.6400

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There is no evidence that there is no significant difference between the sample means

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