Answer: 4 cents or .4
Step-by-step explanation:
Whenever in a problem like this where there is a fee, tax, and or bonus you move the decimal in front of the number and round to the nearest penny but if there is only one number in front of the decimal you don’t gotta do anything with it unless its .5 or higher but .4 and below you keep the same.
Answer: C
Step-by-step explanation:
1 1/8 = 1.125
3/4 = .75
<span>{(3, 7),(3, 6),(5, 4),(4, 7)}not
{(1, 5),(3, 5),(4, 6),(6, 4)}is
{(2, 3),(4, 2),(4, 6),(5, 8)}not
{(0, 4),(3, 2),(4, 2),(6, 5)}is</span>
Answer:
(-3, 4)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtract Property of Equality
<u>Algebra I</u>
- Terms/Coefficients
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = -x + 1
2x + 3y = 6
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em>: 2x + 3(-x + 1) = 6
- Distribute 3: 2x - 3x + 3 = 6
- Combine like terms: -x + 3 = 6
- Isolate <em>x</em> terms: -x = 3
- Isolate <em>x</em>: x = -3
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define equation: y = -x + 1
- Substitute in <em>x</em>: y = -(-3) + 1
- Simplify: y = 3 + 1
- Add: y = 4
So I'm hoping you mean 6, or else the probability is 0. So the possible ways of getting a sum of 6 is 1&5, 2&4, 3&3, 4&2, 5&1. There are 36 different ways of rolling the dice, so divide the 5 possible ways by 36. Then, we need to add the possibility of getting at least one 6 in the roll. It doesn't matter what the other die is, so for each die, the probability is 1/6, and for both, the probability is 2/6. Add this to the probability of getting a sum of 6, and you get your answer.
