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olga nikolaevna [1]
3 years ago
7

THIS IS SIMPLE INTEREST

Mathematics
1 answer:
Bingel [31]3 years ago
6 0

Step-by-step explanation:

mmi got the answer .as : 1

time=1

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A guy wire attached to the top of a radio antenna is anchored to a point on the ground 20 m from the antenna's base. If the wire
gregori [183]

Answer:

the cosine of the angle equals 40.0 m divided by the length of the wire

cos(58º20') = 40.0 m / L

L = 40.0 m / cos(58º20')

Step-by-step explanation:

6 0
3 years ago
10.3.23
Helga [31]

Answer:

The probability that a high school member selected at random is on the swim team is \frac{9}{40} = 0.225

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: High school student.

Event B: Is on the swin team.

Probability of selecting a high school student:

Of the 1500 students, 200 are on high school. So

P(A) = \frac{200}{1500}

Probability of selecting a high school student who swims:

Of the 1500 students, 45 are high school students who swim. So

P(A \cap B) = \frac{45}{1500}

What is the probability that a high school member selected at random is on the swim team?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{\frac{45}{1500}}{\frac{200}{1500}} = \frac{45}{200} = \frac{9}{40} = 0.225

The probability that a high school member selected at random is on the swim team is \frac{9}{40} = 0.225

4 0
2 years ago
Ok this may be hard but I found this on my test ;--;
umka2103 [35]

Answer:

-2383.83870968

Step-by-step explanation:

I hope this is right...

8 0
3 years ago
Arrange the numbers in decreasing order.<br> 83.508<br> 83.58 83.5 83.058
Anna [14]

Answer:

they already are.

in ascending order, they are 83.058, 83.5, 83.58

3 0
3 years ago
Read 2 more answers
Simplify the expression
SashulF [63]

Answer:

1/(c - d)

Step-by-step explanation:

Multiply numerator and denominator by cd, then factor the denominator and cancel the common factor. (The result is restricted to c+d ≠ 0.)

\displaystyle\frac{\frac{1}{c}+\frac{1}{d}}{\frac{c}{d}-\frac{d}{c}}=\frac{d+c}{c^2-d^2}\\\\=\frac{d+c}{(c-d)(d+c)}=\frac{1}{c-d}

4 0
3 years ago
Read 2 more answers
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