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3 years ago

10 POINTS FOR THE CORRECT ANSWER PLEASE HELP ME

Mathematics

2 answers:

Nookie1986 [14]3 years ago

3 0

It's 65 it cuts it in half u only get 5 points

Mashutka [201]3 years ago

3 0

Answer:

10.3

Step-by-step explanation:

6²+b²=9²

36+b²=81

b²=81-36

b²=45

b=√45

b=6.7

So CE is 6.7.

6²+b²=7²

36+b²=49

b²=49-36

b²=13

b=√13

b=3.6

so EA is 3.6

AC = CE+EA = 6.7+3.6 = 10.3

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I need help is 0.7 a rational number?

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Answer:

Yes, because it can be written as 7/10.

Step-by-step explanation:

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What is the slope of this line

kifflom [539]

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3/4

Step-by-step explanation:

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4 years ago

Elliot wrote a computer program that randomly generates a number from 2 to 10. If he runs the program twice, what is the probabi

Vikentia [17]

Answer:

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Step-by-step explanation:

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3 years ago

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33. Suppose you were on a planet where the

tatyana61 [14]

Answer:

a) 3.675 m

b) 3.67m

Explanation:

We are given acceleration due to gravity on earth = $9.8ms^-2$

And on planet given = $2.0ms^-2$

A) Since the maximum jump height is given by the formula

$\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}$

Where H = max jump height,

v0 = velocity of jump,

Ø = angle of jump and

g = acceleration due to gravity

Considering velocity and angle in both cases

$\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}$

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)

g1 = 2.0 $ms^-2$ and

g2 = 9.8 $ms^-2$

Substituting these values we get H1 = 3.675m which is the required answer

B) Formula to find height of ball thrown is given by

$\mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}$

which is due to projectile motion of ball

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write

$\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}$

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0 $ms^-2$ and g2 = 9.8 $ms^-2$

We get h1 = 3.67m which is the required height

6 0

4 years ago

A taut clothesline extends between the points (–4.2, –6.4, 4.5) and (7.1, 2.2, 5.8), where the coordinates are in units of feet.

Citrus2011 [14]

Answer:

17.54 ft

Step-by-step explanation:

Moving along the line from (–4.2, –6.4, 4.5) to (7.1, 2.2, 5.8), x increases by 11.3, y by 8.6 and z by 10.3.

Applying the Pythagorean Theorem twice, we get

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7 0

3 years ago