The series is a convergent p-series with p = 3
<h3>How to know it is a divergent or a convergent series</h3>
We would know that a series is a convergent p series when we have ∑ 1 np. Then you have to be able to tell if the series is a divergent p series or it is a convergent p series.
The way that you are able to tell this is if the terms of the series do not approach towards 0. Now when the value of p is greater than 1 then you would be able to tell that the series is a convergent series.
The value of 
The formular for this is
∑
where n = 1
we know it is convergent because p is greater than 1. 3>1
Read more on convergent series here:
brainly.com/question/337693
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Answer:
where 
= 2
Step-by-step explanation:
512/-8 = -64
difference of n = 3
![\sqrt[3]{64} = 4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D%20%3D%204)
where = 2
Option D equal is your answer ☺️☺️☺️
Answer:
a) 29.23% probability that a randomly selected home run was hit to right field
b) 29.23% probability that a randomly selected home run was hit to right field, which is not lower than 5% nor it is higher than 95%. So it was not unusual for this player to hit a home run to right field.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes. It is said to be unusual if it is lower than 5% or higher than 95%.
(a) What is the probability that a randomly selected home run was hit to right field?
Desired outcomes:
19 home runs hit to right field
Total outcomes:
65 home runs
19/65 = 0.2923
29.23% probability that a randomly selected home run was hit to right field
(b) Was it unusual for this player to hit a home run to right field?
29.23% probability that a randomly selected home run was hit to right field, which is not lower than 5% nor it is higher than 95%. So it was not unusual for this player to hit a home run to right field.
First of all, try to understand the questions then try to make a pair of linear equations. After that make the coefficients of x or y equal in both RFD equations by multiplying them by suitable values then add or subtract them ,in such a way which will terminate any one of the variables. Then find the value of left variable. After that just put the value you have found just now In any of the equations and you'll really get the value of the second variable too.
