All categories

3 years ago

Express 1010two to base ten

Mathematics

1 answer:

lora16 [44]3 years ago

4 0

Answer:Multiply the given fraction (in base 10) with 2.

Step-by-step explanation:

You might be interested in

Which of the following is a step in constructing angle bisectors using a compass and straight edge? a Construct a copy of the li

motikmotik

Answer:

start with a line segment to divide into equal parts

Step-by-step explanation:

that's the first step you take before you make the angle bisector because there's no point in doing the other steps before that

8 0

2 years ago

Read 2 more answers

a Car has a 15 gallon gas tank . I f a car gets 32 miles per gallon and travels 384 miles . how much gas will be left in the tan

Komok [63]

Answer:

so you would actually multiply 32 x 15=480 then subtract 480 - 384= it would have 96 miles left. then divide 96/32= 3

so your answer would be 3 gallons left

Step-by-step explanation:

4 0

2 years ago

Please help I’ll name brainliest

Kipish [7]

Answer:

mark R as a 6

Step-by-step explanation:

6 0

2 years ago

please help me, Prove a quadrilateral with vertices G(1,-1), H(5,1), I(4,3) and J(0,1) is a rectangle using the parallelogram me

mestny [16]

Answer:

Step-by-step explanation:

We are given the coordinates of a quadrilateral that is G(1,-1), H(5,1), I(4,3) and J(0,1).

Now, before proving that this quadrilateral is a rectangle, we will prove that it is a parallelogram. For this, we will prove that the mid points of the diagonals of the quadrilateral are equal, thus

Join JH and GI such that they form the diagonals of the quadrilateral.Now,

JH= $\sqrt{(5-0)^{2}+(1-1)^{2}}=5$ and

GI= $\sqrt{(4-1)^{2}+(3+1)^{2}}=5$

Now, mid point of JH= $(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

= $(\frac{5+0}{2},\frac{1+1}{2})=(\frac{5}{2},1)$

Mid point of GI= $(\frac{5}{2},1)$

Since, mid point point of JH and GI are equal, thus GHIJ is a parallelogram.

Now, to prove that it is a rectangle, it is sufficient to prove that it has a right angle by using the Pythagoras theorem.

Thus, From ΔGIJ, we have

$(GI)^{2}=(IJ)^{2}+(JG)^{2}$ (1)

Now, JI= $\sqrt{(4-0)^{2}+(3-1)^{2}}=\sqrt{20}$ and GJ= $\sqrt{(0-1)^{2}+(1+1)^{2}}=\sqrt{5}$

Substituting these values in (1), we get

$5^{2}=(\sqrt{20})^{2}+(\sqrt{5})^{2} }$

$25=20+5$

$25=25$

Thus, GIJ is a right angles triangle.

Hence, GHIJ is a rectangle.

Also, The diagonals GI= $\sqrt{(4-1)^{2}+(3+1)^{2}}=5$ and HJ= $\sqrt{(0-5)^2+(1-1)^2}=5$ are equal, thus, GHIJ is a rectangle.

6 0

2 years ago

Use ABC to find the value of sin A. <br> a. 12/37<br> b. 37/12<br> c. 35/37<br> d. 12/35

FromTheMoon [43]

Answer:

a. 12/37

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you ...

Sin = Opposite/Hypotenuse

sin(A) = BC/AB = 12/37

4 0

3 years ago

Express 1010two to base ten​

Express 1010two to base ten