Let n be the product of the two smallest 3-digit prime numbers. Find the sum of the digits of n.
1 answer:
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Answer:
1) 11h - 25
2) 8
3) C
Step-by-step explanation:
1) 5h-9+-16+6h
+ and - together makes -
5h - 9 - 16 + 6h
Arrange the like terms together
5h + 6h - 9 - 16
= 11h - (9+16)
= 11h - 25
2) 4x+4=9x-36
Subtract 4x from both sides
4x+4-4x = 9x-36-4x
Cancl out 4x and -4x from the left side
4 = 9x - 4x -36
=> 4 = 5x -36
Add 36 to both sides
4+36 = 5x -36 + 36
Cancel out -36 and +36 from the right side
=> 40 = 5x
Flip both the sides of the equation
5x = 40
Dividing both sides by 5
Cancel out the 5's on the top and bottom of the left side
x = 8
3) 7x+5 = 4x+5+3x
Arrange the like terms together on the right side
7x+5 = 4x+3x+5
=> 7x+5 = 7x+5
Subtract 5 from both sides
7x+5-5 = 7x+5-5
Cancel out +5 and -5 on both the sides
7x = 7x
Divide both sides by 7
Cancel out the 7's from the top and bottom of both sides
x = x
which can be true for infinite value of x like 1=1, 2=2, 3=3,.............