Answer :
Letter C : e = 40,000 + 200 x c
Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
Answer:
(y+b)/a = x
Step-by-step explanation:
y = ax − b
Add b to each side
y+b = ax − b+b
y+b =ax
Divide each side by a
(y+b)/a = ax/a
(y+b)/a = x
If you mean by completely factored form of x^4y - 4x2y - 5y
Then the answer is y (x^2 - 5) (x^2 + 1)
3/4 * 2/3 = > 6/12 ; Then you simplify it and the answer will be 1/2. Therefore the fraction of the students who participated in a school club/sports team is 1/2.
