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Katena32 [7]
3 years ago
14

The table shows the effect of education on annual income. Based on the data in the table, how much more does a person with an Ba

chelor’s degree earn than a person with only a high school diploma over 10 years?
A) $20,800
B) $29,690
C) $208,000
D)$290,690

Mathematics
1 answer:
yuradex [85]3 years ago
6 0

B is the correct answer

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Let a=3/5 and let b=2/3. Compute a^2b^-3.
Amanda [17]

Answer: 81/100



Step-by-step explanation:

I don't guarantee you I am right but..

first, solve for the exponents after substituting the numbers in

3/5 x 3/5 is 9/25

since b's exponent is negative, you change the fraction into its reciprocal and then do it with the exponent but positive

2/3^-3 to 3/2^3 and 3/2 x 3/2 is 9/4

then you mutiply both numbers to get 9/4 x 9/25 is 81/100

7 0
2 years ago
Job a, $15/hour, job b, $12/hour, how many hours at each job to earn $360
stira [4]

Answer:

Job A, will take 24 hours and Job B, will take 30 hours

Step-by-step explanation:

12 X 30 = 360 and 15 X 24 = 360

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2 years ago
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How much packing material is needed to fill the empty space in the bag
likoan [24]
About 102.5625... I think

5 0
3 years ago
Te: 6 less then a number cubed
telo118 [61]

Answer:

x^ 3 -6

Step-by-step explanation:

x^ 3- 6

cubed x first. then subtract 6 from that

6 0
3 years ago
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Suppose a marketing company wants to determine the current proportion of customers who click on ads on their smartphones. It was
andrezito [222]

Answer:

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 100, p = 0.42

92% confidence level

So \alpha = 0.08, z is the value of Z that has a pvalue of 1 - \frac{0.08}{2} = 0.96, so Z = 1.75.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 1.75\sqrt{\frac{0.42*0.58}{100}} = 0.3336

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 1.75\sqrt{\frac{0.42*0.58}{100}} = 0.5064

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).

4 0
3 years ago
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