The 3rd one. (where the round part of the graph is at 0, 0) because that is where the y axis meets
Answer:
Step-by-step explanation:
One of the easier approaches to graphing a linear equation such as this one is to solve it for y, which gives us both the slope of the line and the y-intercept.
x-3y=-6 → -3y = -x - 6, or 3y = x + 6.
Dividing both sides by 3, we get y = (1/3)x + 2.
So the slope of this line is 1/3 and the y-intercept is 2.
Plot a dot at (0, 2). This is the y-intercept. Now move your pencil point from that dot 3 spaces to the right and then 1 space up. Draw a line thru these two dots. End.
Alternatively, you could use the intercept method. We have already found that the y-intercept is (0, 2). To find the x-intercept, let y = 0. Then x = -6, and the x-intercept is (-6, 0).
Plot both (0, 2) and (-6, 0) and draw a line thru these points. Same graph.
You can add, subtract, and multiply them. These three operations obey the rules for integers. There's a polynomial division algorithm that fills formally the same role as the usual division algorithm for integers. Polynomials added to, subtracted from, or multiplied by other polynomials yield only polynomials. Likewise, integers added to, subtracted from, or multiplied by other integers yield only integers.
The formula of the sum of a geometric sequence:
We have:
substitute:
Answer: C. -5460
Answer:
Step-by-step explanation:
A person invested $2,500 in an account growing at a rate allowing the money to double every 11 years. How long, to the nearest tenth of a year would it take for the
value of the account to reach $3,800?
The formula for exponential growth given as:
A(t) = Ao (1/2)^t/t½
A(t) = Amount after time t = $3,800
Ao = Initial amount invested = $2500
t = Time in years
t½ = Time it takes to double = 11 years
Hence,
3800 = 2500(1/2)^t/11
Divide both sides by 2500
3800/2500 = 2500(1/2)^t/11/2500
