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Archy [21]
3 years ago
7

Pls help me with this question bc it’s for a test

Mathematics
2 answers:
barxatty [35]3 years ago
8 0

Answer:

50%

Step-by-step explanation:

boyakko [2]3 years ago
6 0

Answer:

50%

Step-by-step explanation:

The total students are 80 + 70 = 150

the total students that arrive in automobile are: 51 + 24 = 75

we have to use a proportion to answer the question:

x : 100 = 75 : 150

x = (75*100)/150 = 50

You might be interested in
18 is 75% of what number?
Nonamiya [84]

Answer:

24

Step-by-step explanation:

18 * 4 /3 = 72/3 = 24

8 0
3 years ago
Read 2 more answers
Two numbers have a product of -36<br> They have a sum of -5<br> What are the two numbers?
neonofarm [45]

Answer:

-9,4

Step-by-step explanation:

4 0
2 years ago
Write an expression for the calculation 84 divided into sevenths added to 9 divided into thirds
kogti [31]
(84/7)+ 9/3=
     12+9/3
       12+3
          15




7 0
4 years ago
What are the steps to solving this problem K + 8\5 = 1k
DaniilM [7]

-- Subtract K from each side of the equation.

8/5 = 0

-- There is no value for K that can make this a true statement. So the original equation has no solution.

8 0
3 years ago
Solve dis attachment and show all work ( I got it all wrong and I want to know how to solve it )
DedPeter [7]
(a) First find the intersections of y=e^{2x-x^2} and y=2:

2=e^{2x-x^2}\implies \ln2=2x-x^2\implies x=1\pm\sqrt{1-\ln2}

So the area of R is given by

\displaystyle\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}\left(e^{2x-x^2}-2\right)\,\mathrm dx

If you're not familiar with the error function \mathrm{erf}(x), then you will not be able to find an exact answer. Fortunately, I see this is a question on a calculator based exam, so you can use whatever built-in function you have on your calculator to evaluate the integral. You should get something around 0.5141.

(b) Find the intersections of the line y=1 with y=e^{2x-x^2}.

1=e^{2x-x^2}\implies 0=2x-x^2\implies x=0,x=2

So the area of S is given by

\displaystyle\int_0^{1-\sqrt{1-\ln2}}\left(e^{2x-x^2}-1\right)\,\mathrm dx+\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}(2-1)\,\mathrm dx+\int_{1+\sqrt{1-\ln2}}^2\left(e^{2x-x^2}-1\right)\,\mathrm dx
\displaystyle=2\int_0^{1-\sqrt{1-\ln2}}\left(e^{2x-x^2}-1\right)\,\mathrm dx+\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}\mathrm dx

which is approximately 1.546.

(c) The easiest method for finding the volume of the solid of revolution is via the disk method. Each cross-section of the solid is a circle with radius perpendicular to the x-axis, determined by the vertical distance from the curve y=e^{2x-x^2} and the line y=1, or e^{2x-x^2}-1. The area of any such circle is \pi times the square of its radius. Since the curve intersects the axis of revolution at x=0 and x=2, the volume would be given by

\displaystyle\pi\int_0^2\left(e^{2x-x^2}-1\right)^2\,\mathrm dx
5 0
3 years ago
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