Find the equation of the line that is perpendicular to y = - 1/3 x + 2 and passes though the point (-5,2)

Mathematics

1 answer:

elena55 [62]3 years ago

6 0

Answer:

y - 2 = 3(x + 5)

Step-by-step explanation:

The given equation has slope -1/3. Any line perpendicular to the given line has a slope which is the negative reciprocal of -1/3, which comes out to +3.

Use the point-slope formula y - k = m(x - h):

y - 2 = 3(x + 5)

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Let f(x) represent a function.

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For $f(x+\frac{5}{4})$ , $f(x)$ is translated $\frac{5}{4}$ units left.

For $f(x)-\frac{5}{4}$ , $f(x)$ is translated $\frac{5}{4}$ units down.

Step-by-step explanation:

The transformation of $f(x)\rightarrow f(x+C)$ means that the graph shift to left by C units if C is positive number and shifts to right by C units if C is a negative number.

The transformation of $f(x)\rightarrow f(x)+C$ means that the graph shifts up by C units if C is positive number and shifts down by C units if C is a negative number.

Here, in the transformation of $f(x)\rightarrow f(x+\frac{5}{4}),C = \frac{5}{4}>0$ , so, the function translates left by $\frac{5}{4}$ units.

Similarly, in the transformation of $f(x)\rightarrow f(x)-\frac{5}{4},C = -\frac{5}{4}$ , so, the function translates down by $\frac{5}{4}$ units.