Answer:
He can run 137.5 ft
Step-by-step explanation:
We can use a proportion to solve
55 ft x ft
--------------- = -----------------
10 seconds 25 seconds
55 *25 = x*10
1375 = 10x
Divide each side by 10
1375/10 = 10x/10
137.5 = x
He can run 137.5 ft
Since 36 = 36^1 I would say the exponent is 1
Answer:
Step-by-step explanation:
Given :
In the given quadrilateral ABCD,
BN and DM are the perpendiculars drawn to AC such that,
BN = DM
To prove:
Point O is the midpoint of segment BD.
Or
OD = OB
Solution:
In ΔOMD and ΔONB,
∠MOD ≅ NOB [Vertical angles]
∠M ≅ ∠N ≅ 90° [Given]
Therefore, by AA property of similarity,
ΔOMD ~ Δ ONB
Therefore, their corresponding sides will be proportional,
Since BN = DM,
OD = OB
Hence O is the midpoint of BD.
Step-by-step explanation:
f(x)=5x-3
g(x)=5x-4
f(g(x))
f(5x-4)=5(5x-4)-3
25x-20-3
=25x-23
I would appreciate if my answer is chosen as a brainliest answer
To solve this problem you must follow the proccedure below:
a<span>. Find the perimeter and area of the cracker remaining:
The perimeter of a quarter circle is:
P=(</span>πr/2)+2r
P=(πx3 cm/2)+2(3 cm)
P=10.71 cm
The perimeter of <span>the cracker remaining is:
</span><span>
Pt=3 cm+6 cm+3 cm+10.71 cm
Pt=22.71 cm
The area of a quarter circle is:
A=</span>πr²/4
A=π(3 cm)²/4
A=7.06 cm²
<span>
The area of</span><span>of the cracker remaining is:
</span><span>
At=Area of a square-Area of quarter circle
At=L</span>²-(πr²/4)
At=(6 cm)²-(π(3 cm)²/4)
At=28.93 cm²
<span>
b. About how many bites can you get from the entire cracker?</span>
Number of bites=L²/(π(3 cm)²/4)
Number of bites=5
