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Nonamiya [84]
3 years ago
7

Have an amazing day :) Will give brainlst

Mathematics
1 answer:
vova2212 [387]3 years ago
6 0
Answer: 8.3 in.

Steps:
a^2 + b^2 = c^2
a^2 + 18.2^2 = 20^2
a^2 + 331.24 = 400
a^2 = 400 - 331.24
a^2 = 68.76
a = 8.29
a = 8.3
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Solution:
1x +2x -7 =0

3x-7=0

Add 7 To Both Sides Of The Equal Sign Then Divide By 3
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TRUE OR FALSE LOOK THE PHOTO RENAE HELP ME FIRST LOL
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Answer: theres no photo ?

Step-by-step explanation:

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3 years ago
It has been suggested that night shift-workers show more variability in their output levels than day workers. Below, you are giv
bonufazy [111]

Answer:

Null hypotheses = H₀ = σ₁² ≤ σ₂²

Alternative hypotheses = Ha = σ₁² > σ₂²

Test statistic = 1.9

p-value = 0.206

Since the p-value is greater than α therefore, we cannot reject the null hypothesis.

So we can conclude that the night shift workers don't show more variability in their output levels than day workers.

Step-by-step explanation:

Let σ₁² denotes the variance of night shift-workers

Let σ₂² denotes the variance of day shift-workers

State the null and alternative hypotheses:

The null hypothesis assumes that the variance of night shift-workers is equal to or less than day-shift workers.

Null hypotheses = H₀ = σ₁² ≤ σ₂²

The alternate hypothesis assumes that the variance of night shift-workers is more than day-shift workers.

Alternative hypotheses = Ha = σ₁² > σ₂²

Test statistic:

The test statistic or also called F-value is calculated using

Test statistic = Larger sample variance/Smaller sample variance

The larger sample variance is σ₁² = 38

The smaller sample variance is σ₂² = 20

Test statistic = σ₁²/σ₂²

Test statistic = 38/20

Test statistic = 1.9

p-value:

The degree of freedom corresponding to night shift workers is given by

df₁ = n - 1

df₁ = 9 - 1

df₁ = 8

The degree of freedom corresponding to day shift workers is given by

df₂ = n - 1

df₂ = 8 - 1

df₂ = 7

We can find out the p-value using F-table or by using Excel.

Using Excel to find out the p-value,

p-value = FDIST(F-value, df₁, df₂)

p-value = FDIST(1.9, 8, 7)

p-value = 0.206

Conclusion:

p-value > α    

0.206 > 0.05   ( α = 1 - 0.95 = 0.05)

Since the p-value is greater than α therefore, we cannot reject the null hypothesis corresponding to a confidence level of 95%

So we can conclude that the night shift workers don't show more variability in their output levels than day workers.

3 0
3 years ago
Which input value produces the same output value for the two functions on the graph
schepotkina [342]
You've got it right. It is -2.
when x=-2, both line have the same y value 1.
4 0
3 years ago
Read 2 more answers
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