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3 years ago

13

16. The Venn diagram below represents two sets of numbers.

1 answer:

Andrews [41]3 years ago

8 0

<h3>Answer: D) Rational Numbers</h3>

Any rational number is in the form p/q, where p,q are integers and q is nonzero.

If we made q = 1, then p/q turns into an integer which is why the set of integers is inside the set of rational numbers.

For instance, if p = 7 and q = 1, then p/q = 7/1 = 7 is an integer and it is rational too.

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Ms. Cebrera counted the number of absences each student in her class had last year.

sergejj [24]

The best answer would be c

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3 years ago

PLZ HELP FAST <br><br> If you spend $3 on 6b apples, what is the unit rate (in dollars) per apple?

Ierofanga [76]

Answer:.

.50

Step-by-step explanation:

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3 years ago

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A scientist is growing bacteria in a lab for study. One particular type of bacteria grows at a rate of y=2t^2+3t+500. A differen

Leya [2.2K]

ANSWER

Approximately after 15 minutes.

EXPLANATION

The growth rate of the first bacteria is

$y = 2 {t}^{2} + 3t + 500$

The growth rate of the first bacteria :

$y = 3 {t}^{2} + t + 300$

To find the time that, there will be an equal number of bacteria, we equate the two equation;

$3 {t}^{2} + t + 300 = 2 {t}^{2} + 3t + 500$

$3 {t}^{2} - 2 {t}^{2} + t - 3t + 300 - 500 =00$

${t}^{2} - 2t - 200= 0$

We solve for t to get,

$t = 15.177$

Or

$t = - 13.177$

We discard the negative value.

This implies that,

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3 years ago

The largest set of x values satisfying

velikii [3]

Answer:

If $p\ge -\dfrac{1}{3},$ then $x>\dfrac{2}{3}+p$ and $mn=\dfrac{2}{3}+p=\left(\dfrac{2}{3}+p\right)\cdot 1,\ \ m+n=\dfrac{5}{3}+p$

Step-by-step explanation:

Solve two inequalities for x.

1. $2,018x-p$

Separate terms with x and without x into two sides:

$2,018x-2,020x$

Multiply by -1:

$2x>-2p\\ \\x>-p$

2. $7x+3p$

Separate terms with x and without x into two sides:

$7x-10x$

Multiply by -1:

$3x>2+3p\\ \\x>\dfrac{2}{3}+p$

Find the largest set of x values satisfying both inequalities:

$x>-p\\ \\x>\dfrac{2}{3}+p$

If

$-p>\dfrac{2}{3}+p\\ \\-2p>\dfrac{2}{3}\\ \\2p$

then $x>-p$ and $mn=-p=p\cdot (-1),\ m+n=p-1.$ In this case both m and n are negative.

If $p>-\dfrac{1}{3},$ then $x>\dfrac{2}{3}+p$ and $mn=\dfrac{2}{3}+p=\left(\dfrac{2}{3}+p\right)\cdot 1,\ \ m+n=\dfrac{5}{3}+p$

If $p=-\dfrac{1}{3},$ then $x>\dfrac{1}{3}$ and $mn=\dfrac{1}{3}=\dfrac{1}{3}\cdot 1,\ \ m+n=\dfrac{4}{3}$

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3 years ago

Determine the slope <br> A.2/5 B.-3/8 C.-5/2

gogolik [260]

Answer:-5 per 2

Step-by-step explanation:m= y1-y2perx1-x2

=–8–7per–4–2 = –15per–6 = –5 per 2

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3 years ago

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