Question

The actual amount in a 12-ounce container of a certain brand of orange juice is normally distributed with mean μ = 12.34 ounces and standard deviation σ = 0.04 ounce. What percentage of the juice bottles contain between 12.24 and 12.30 ounces of orange juice?

Answer 1

Answer:

15.25%

Step-by-step explanation:

The actual amount in a 12-ounce container of a certain brand of orange juice is normally distributed with mean μ = 12.34 ounces and standard deviation σ = 0.04 ounce. What percentage of the juice bottles contain between 12.24 and 12.30 ounces of orange juice?

We solve using the z score formula

z-score is is z = (x-μ)/σ,

where x is the raw score

μ is the population mean = μ = 12.34 ounces

σ is the population standard deviation = σ = 0.04 ounce

For x = 12.24

z = 12.24 - 12.34/0.04

z = -2.5

Probability value from Z-Table:

P(x = 12.24) = 0.0062097

For x = 12.30

z= 12.30 - 12.34/0.04

z = -1

Probability value from Z-Table:

P(x = 12.30) = 0.15866

Hence, the probability of the juice bottles contain between 12.24 and 12.30 ounces of orange juice

P(x = 12.30) - P(x = 12.24)

= 0.15866 - 0.0062097

= 0.1524503

Therefore, the percentage of the juice bottles contain between 12.24 and 12.30 ounces of orange juice is calculated as:

= 0.1524503 × 100

= 15.24503%

= 15.25%