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
Square both sides:


Since

is positive, you can discard the negative sign. So,

Substitute this value back into

to find


I hope this helps. =)
Tags: <em>trigonometric identity relation trig sine cosine tangent sin cos tan trigonometry precalculus</em>
Answer:
B. Same distance and same direction
Step-by-step explanation:
The points have to move together while maintaining the same shape.


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
A dog is moving at a constant speed of 8 m/s, that concludes that there's no change in its speed with respect to time.
And Acceleration is define as rate of change in velocity, but since velocity/speed is constant. change in velocity = 0
Henceforth, Acceleration of dog is 0 as well.
Answered by : ❝ AǫᴜᴀWɪᴢ ❞