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3 years ago

10

Joe's cell phone plan costs him $21 per month plus $3 for every 1 GB of data downloaded. What is the limit to the number of Gb's

he can download to stay within his monthly budget of $30?

1 answer:

DIA [1.3K]3 years ago

7 0

3 GB every month..... 21+3=24+3=27+3=30....so 3 GB

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For a class trip, a total of 116 ticket need to be purchased. The cost of an adult ticket is $17000. The cost of a child ticket

zhuklara [117]

Answer:

the price of child tickets are 4,250. how many adult tickets were sold is 91. how many child tickets were sold is 25. which adds up to 1,653,250. your welcome.

Step-by-step explanation:

1,547,000 + 106,250 = 1,653,250

17000 - 12,750(75%) =4,250

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3 years ago

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Mrs. Chan buys a new car for $21,000. She pays a sales tax of $0.06 for every $1. She pays a property tax of $16.80 on every $1,

lianna [129]

Answer:

$1612.80

Step-by-step explanation:

<u>Sales Tax</u> would be 0.06 * 21,000 = $1260

<u>Property Tax:</u>

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So the property tax would be 16.80 * 21 = $352.80

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3 years ago

Stanley makes paper constellations. The following data points represent how many stars were in each

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Answer:

Check Explanation and the attached image.

Step-by-step explanation:

The histogram of the set of data presented is presented in the attached image to.this solution

The histogram represents data by indicating the frequency of distribution on the y-axis and the sets of variables indicated on the x-axis.

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3 years ago

The mean number of daily surgeries at a local hospital is 6.2. Assume that surgeries are random, independent events. (a) The cou

Scilla [17]

Answer:

a) correct option is

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b) probability for only 2 or less than 2 surgeries in a given day is 0.0536

Step-by-step explanation:

Given data:

mean number is given as 6.2

correct option is

Poisson distribution is 6.2 and standard deviation is 2.49

we know that variance is given as $\sigma^2 = mean = 6.2$

hence, standard deviation is given as $\sqrt{6.2} = 2.48998$

thus standard deviation is 2.49

correct option is

Poisson distribution is 6.2 and standard deviation is 2.49

b) probability for only 2 or less than 2 surgeries in a given day is

$P(X \leq 2) = P(X =0) + P(X =1) + P(X =2)$

$= \frac{e^{-6.2} 6.2^0}{0!} +\frac{e^{-6.2} 6.2^1}{1!} +\frac{e^{-6.2} 6.2^2}{2!}$

= 0.002029 + 0.012582+ 0.039006

= 0.053617

= 0.0536

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