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3 years ago

If you help I'll mark as brilliant!!!

Mathematics

1 answer:

inna [77]3 years ago

7 0

Answer:

I had 16/5 instead of 5/16

Step-by-step explanation:

10 (a+b) = 42a

10a + 10b =42a

10b = a( 42 - 10)

(10)b = a(32)

32 /10 = a/b

16/5 = a /b

Ratio of a to b = 16 : 5

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Given that tan theta = -4/7, and 270° < theta < 360°, what is the exact value of sec theta

aleksley [76]

Answer:

sec Θ = $\frac{\sqrt{65} }{7}$

Step-by-step explanation:

Using the trigonometric identity

sec²Θ = tan²Θ + 1

Since 270° < Θ < 360° ← that is fourth quadrant, then

sec Θ > 0, thus

sec²Θ = (- $\frac{4}{7}$ )² + 1 = $\frac{16}{49}$ + 1 = $\frac{65}{49}$ , then

sec Θ = $\sqrt{\frac{65}{49} }$ = $\frac{\sqrt{65} }{7}$

6 0

3 years ago

Consider the random variables X and Y with joint density function ???? f(x,y)= x+y, 0≤x≤1;0≤y≤1 0, elsewhere. (a) Find the margi

sp2606 [1]

a. The marginal densities

$f_X(x)=\displaystyle\int_0^1(x+y)\,\mathrm dy=x+\frac12$

and

$f_Y(y)=\displaystyle\int_0^1(x+y)\,\mathrm dx=y+\frac12$

b. This can be obtained by integrating the joint density over [0.25, 1] x [0.5, 1]:

$P(X>0.25,Y>0.5)=\displaystyle\int_{1/4}^1\int_{1/2}^1(x+y)\,\mathrm dx\,\mathrm dy=\frac{33}{64}$

7 0

3 years ago

Please Help I Have No Idea What They Talking Bout

Black_prince [1.1K]

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4 years ago

Find the altitude and area of an equilateral triangle

Nataliya [291]

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3 years ago

On a cold February morning, the radiator fluid in Stanley’s car is -18 degrees When the engine is running, the temperature goes

Rasek [7]

Remark

This is an arithmetic progression. You have the first and last terms and the difference.

Givens

a = - 18

L = 60

d = 4.5

Equation

L = a + (n - 1)d

Solve

60 = -18 + (n - 1) * 4.5 Add 18 to both side

60 + 18 = (n - 1) * 4.5

78 = (n - 1) * 4.5 Divide both sides by 4.5

78/4.5 = n - 1

17.3333 = n - 1 Add 1 to both sides.

18.3333 = n

Conclusion

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3 years ago

If you help I'll mark as brilliant!!!​

If you help I'll mark as brilliant!!!