a rectangular parking lot has an area of 2/3 of a square kilometer. the width is 1/2 of a kilometer. what is the length, in kilo
1 answer:
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Answer:
Semicircle of radius of 1.6803 meters
Rectangle of dimensions 3.3606m x 1.6803m
Step-by-step explanation:
Let the radius of the semicircle on the top=r
Let the height of the rectangle =h
Since the semicircle is on top of the window, the width of the rectangular portion =Diameter of the Semicircle =2r
The Perimeter of the Window
=Length of the three sides on the rectangular portion + circumference of the semicircle
The area of the window is what we want to maximize.
Area of the Window=Area of Rectangle+Area of Semicircle
We are trying to Maximize A subject to
The first and second derivatives are,
Area, A(r)
Taking the first and second derivatives
From the two derivatives above, we see that the only critical point of r
Since the second derivative is a negative constant, the maximum area must occur at this point.
So, for the maximum area the semicircle on top must have a radius of 1.6803 meters and the rectangle must have the dimensions 3.3606m x 1.6803m ( Recall, The other dimension of the window = 2r)
Answer:
6 students at the preschool of four years old attended the full day program.
Step-by-step explanation:
Given:
Number of four years old students = 16
fraction of four years old students attended full day program =
We need to find the number of four years old students attended the full day program.
Solution:
Now we can say that;
number of four years old students attended the full day program is equal to fraction of four years old students attended full day program multiplied by Number of four years old students.
framing in equation form we get;
number of four years old students attended the full day program =
Hence 6 students at the preschool of four years old attended the full day program.
Answer:
Brainliest????
Step-by-step explanation:
X=23°
