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2 years ago

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Factor 15x^2y^2 - 3x^3y + 75x^4. Show your work. Need to show work and please be 100% honest. Only answer if you know how. Will

Mark Brainliest.

2 answers:

snow_lady [41]2 years ago

7 0

Answer:

3x^2(25x^2−xy+5y^2)

Step-by-step explanation:

I copied it into MathPapa and it is always correct. It gave me that

lyudmila [28]2 years ago

6 0

Answer:

3x2 • (25x2 + xy + 5y2)

Step-by-step explanation:

thank me later

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Work out the size of angle x

vfiekz [6]

Answer:

104 degrees

Step-by-step explanation:

90 + 54 + 132 = 276

360 - 276 = 104

6 0

3 years ago

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What's 789,091 rounded to the hundred thousands

Elena-2011 [213]

We need to round the number to the nearest hundred throusands.
this means that we will check the number after the poaition of the hundred thousands, if it is 5 or more,then we will add one otherwise we will ignore it and add zeros.
based on this, the number in the position next to the hundred thousands is 8 which mean that we will add one to the hundred thousands positions while all others will become zero.
Therefore,
789,091 to the nearest hundred thousands is 800,000

7 0

3 years ago

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Solve the equation by using the quadratic formula.<br> 8x2 – 2x - 15 =0

ddd [48]

Answer:

x = 3/2 or x = -5/4

Step-by-step explanation:

Solve for x over the real numbers:

8 x^2 - 2 x - 15 = 0

Using the quadratic formula, solve for x.

x = (2 ± sqrt((-2)^2 - 4×8 (-15)))/(2×8) = (2 ± sqrt(4 + 480))/16 = (2 ± sqrt(484))/16:

x = (2 + sqrt(484))/16 or x = (2 - sqrt(484))/16

Simplify radicals.

sqrt(484) = sqrt(4×121) = sqrt(2^2×11^2) = 2×11 = 22:

x = (2 + 22)/16 or x = (2 - 22)/16

Evaluate (2 + 22)/16.

(2 + 22)/16 = 24/16 = 3/2:

x = 3/2 or x = (2 - 22)/16

Evaluate (2 - 22)/16.

(2 - 22)/16 = -20/16 = -5/4:

Answer: x = 3/2 or x = -5/4

4 0

2 years ago

Let n be a natural number. Show that 3 | n3 −n

Vladimir [108]

Let $n=1$ . Then $n^3-n=1^3-1=0$ . By convention, every non-zero integer $n$ divides 0, so $3\vert n^3-n$ .

Suppose this relation holds for $n=k$ , i.e. $3\vert k^3-k$ . We then hope to show it must also hold for $n=k+1$ .

You have

$(k+1)^3-(k+1)=(k^3+3k^2+3k+1)-(k+1)=(k^3-k)+3(k^2+k)$

We assumed that $3\vert k^3-k$ , and it's clear that $3\vert 3(k^2+k)$ because $3(k^2+k)$ is a multiple of 3. This means the remainder upon divides $(k+1)^3-(k+1)$ must be 0, and therefore the relation holds for $n=k+1$ . This proves the statement.

4 0

3 years ago

Honors Geometry QUiz- Please Help

viktelen [127]

Answer:

QUESTION 2:

The area of the polygon is 21.5 units²

QUESTION 3:

The area of the combined figure is 12 + 18.25·π units²

QUESTION 4:

The area of the figure is 40 units²

QUESTION 5

The area of the compost shape is 40 in.²

Step-by-step explanation:

QUESTION 2.

The area of the polygon is given as follows;

The area of two triangles + The area of trapezoid

1/2×6×3 + 1/2×3×4 + 1/2×(6 + 7) = 21.5 units²

QUESTION 3

The diameter of the semicircle, 'd', is given as follows;

d = √(8² + 3²) = √73

The area of the semicircle = π·d²/4 = π·73/4 = 18.25·π unit²

The area of the right triangle beside the semicircle is given as follows;

1/2 × 8 × 3 = 12 unit²

The area of the combined figure = The area of the semicircle + The area of the right triangle

∴ The area of the combined figure = 12 + 18.25·π units²

QUESTION 4:

The dimensions of the parallelogram are;

Width, W = √(4² + 1²) = √(17)

Length, L = √(8² + 2²) = √(68)

The area of the parallelogram, $A_R$ = W × L = √(17) × √(68) = √(17 × 68) = 34

The area of the parallelogram, $A_R$ = 34 units²

The length of a parallel side, 'A', of the parallelogram is A = 6

The height of the parallelogram, is h = 1

The area of the parallelogram is A = B·h = 6 × 1 = 6 units²

The area of the figure is the sum of the area of the rectangle and the area of the parallelogram

Therefore, we have;

The area of the figure = 34 units² + 6 units² = 40 units²

QUESTION 5

The composite shape consists of a triangle and a rectangle

Therefore, we have;

The area of the rectangle = 5 in. × 7 in. = 35 in.²

The area of the triangle = 1/2 × 2 in. × 5 in. = 5 in.²

The area of the compost shape = The area of the rectangle + The area of the triangle

∴ The area of the compost shape = 35 in.² + 5 in.² = 40 in.²

The area of the compost shape = 40 in.².

5 0

3 years ago