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schepotkina [342]

2 years ago

5

In 2015, the population of a town was 8914. The population is expected to grow at a rate of 1.36% each year. At this rate, what

would be the population in 2040? Round to the nearest whole number. Enter your answer in the box.

1 answer:

wolverine [178]2 years ago

7 0

Answer:

320904

Step-by-step explanation:

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Help pls!! I’ll give Brainlist!! For questions 1-5 determine if the quadrilaterals are parallelograms or not. Beside the picture

tia_tia [17]

Answer:

1. no

2. yes

3. yes

4. yes

5. no

Step-by-step explanation:

plz mark me as brainliest

8 0

2 years ago

Read 2 more answers

Which choice shows the coordinates of B’ if the trapezoid is reflected across the x-axis?

Strike441 [17]

For this case we have that the original point is given by:
B = (7, 2)
As the point is reflected through the x axis, then we have the following transformation:
(x, y) --------------> (x, -y) -------------> (x ', y')
Applying the transformation to the original ordered pair we have:
(7, 2) --------------> (7, - (2)) -------------> (7, -2)
Answer:
Point B 'is given by:
B '= (7, -2)

8 0

2 years ago

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-2(8w+13)+9w=-61 what does w represent

zaharov [31]

-16w-26+9w=-61
-16w+9w=-61+26
-7w=-35
w=5

3 0

2 years ago

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(e) the equations of the asymptotes (enter your answers as a comma-separated list of equations.)

nexus9112 [7]

Answer:

x=3,x=1

y=2,y=-2

Step-by-step explanation:

4 0

2 years ago

You are planning a survey of starting salaries for recent computer science majors. In a recent survey by the National Associatio

nydimaria [60]

Answer:

A sample size of 554 is needed.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.025 = 0.975$ , so Z = 1.96.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

Standard deviation is known to be $12,000

This means that $\sigma = 12000$

What sample size do you need to have a margin of error equal to $1000, with 95% confidence?

This is n for which M = 1000. So

$M = z\frac{\sigma}{\sqrt{n}}$

$1000 = 1.96\frac{12000}{\sqrt{n}}$

$1000\sqrt{n} = 1.96*12$

Dividing both sides by 1000:

$\sqrt{n} = 1.96*12$

$(\sqrt{n})^2 = (1.96*12)^2$

$n = 553.2$

Rounding up:

A sample size of 554 is needed.

5 0

2 years ago