3 years ago

Proprietors' Income $20

Mathematics

1 answer:

kiruha [24]3 years ago

8 0

Answer

I don't know

search it in g

oogle

You might be interested in

Please answer my question .q bo 4 d and e

sdas [7]

4 (e)
sin^8 x - cos^8 x
= (sin^4 x + cos^4 x)(sin^4 x - cos^4 x)
= (sin^4 x + cos^4 x)(sin^2 x - cos^2x)(sin^2 x +cos^2 x)
= (sin^4x + cos^4 x)( sin^2 x- cos^2 x)

Sorry I cant do 4 (d).

5 0

3 years ago

Solve for x. Round to the nearest tenth, if necessary. 1.8 & x

Valentin [98]

Answer:

x ≈ 1.4

Step-by-step explanation:

Using the sine ratio in the right triangle

sin50° = $\frac{opposite}{hypotenuse}$ = $\frac{RS}{RT}$ = $\frac{x}{1.8}$ ( multiply both sides by 1.8 )

1.8 × sin50° = x , then

x ≈ 1.4 ( to the nearest tenth )

7 0

3 years ago

What is the area of the pentagon below?<br> 12.5 m<br> 20 m<br> 25 m<br> 27.5 m

igor_vitrenko [27]

20 m is the pentagon area

5 0

3 years ago

Read 2 more answers

Help me pleaseeeeeeEEEEEE

Sliva [168]

15. 22=4*5+2
16. 23=3+4*5

7 0

2 years ago

Jethro has paid his annual taxes.He knows that his tax is 27% of his taxable income.If he made $68,000 last year,which proportio

Hatshy [7]

Answer:

$\frac{x}{68,000}= \frac{27}{100}$

Step-by-step explanation:

Let

x ----> amount that Jethro owes in taxes

we know that

Amount that he made last year $\$68,000$

His tax rate $27\%=\frac{27}{100}$

Applying proportion

$\frac{x}{68,000}= \frac{27}{100}$

solve for x

$x=68,000(27)/100\\x=\$18,360$

4 0

3 years ago