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4 years ago

Determine whether each ordered pair is a solution of the system.

Mathematics

1 answer:

Stolb23 [73]4 years ago

8 0

According to the system:

5 – 7x + 2y² = -10

1 – 5x – 2y = -22

______________

a) No ; (4, 6) is not a solution to the

system. This point does not touch either equation.

b) No ; (6, 4) is not a solution to the system. This point does not touch either equation.

Solutions:

$( \frac{122 - 3 \sqrt{101}}{25}, \frac{ - 7 +3 \sqrt{101}}{10}) ≈ (3.674, 2.315) \\ ( \frac{122 + 3 \sqrt{101}}{25}, \frac{ - 7 - 3 \sqrt{101}}{10}) ≈ (6.086, -3.715)$

x = ( 122 ∓ 3√101 ) / 25 ≈ 3.674 or 6.086

y = ( -7 ± 3√101 ) / 10 ≈ 2.315 or -3.715

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A sample of n = 10 automobiles was selected, and each was subjected to a 5-mph crash test. Denoting a car with no visible damage

solmaris [256]

Answer:

a) From definition the proportion of successes would be:

$\hat p = \frac{x}{n} = \frac{7}{7+3}= 0.7$

b) Data : 1,1,0,0,1,1,1,0,1,1

x = 7 for this case

$\hat p = \frac{7}{10}=0.7$

The proportion in part (a) is exactly equal to the mean in part (b)

c) We have actually 7 successes and 3 fails and we want this condition:

$\frac{x}{n}=0.6$

The new value of n would be 25 so then we can solve for x and we got:

$x = 25*0.6= 15$

So we need 15 successes and we have 7 so then we need $15-7 = 8$ successes in the new 15 cars in order to satisfy the condition.

Step-by-step explanation:

Data: S S F F S S S F S S

S means success and F damage. We have 7 successes and 3 damages for this case

(a) What is the value of the sample proportion of successes x/n?(

From definition the proportion of successes would be:

$\hat p = \frac{x}{n} = \frac{7}{7+3}= 0.7$

(b) Replace each S with a 1 and each F with a 0. Then calculate x for this numerically coded sample.How does x compare with x/n?

Data : 1,1,0,0,1,1,1,0,1,1

x = 7 for this case

$\hat p = \frac{7}{10}=0.7$

The proportion in part (a) is exactly equal to the mean in part (b)

(c) Suppose it is decided to include 15 more cars in the experiment. How many of these would have to be S's to give x/n = 0.6 for the entire sample of 25 cars?

We have actually 7 successes and 3 fails and we want this condition:

$\frac{x}{n}=0.6$

The new value of n would be 25 so then we can solve for x and we got:

$x = 25*0.6= 15$

So we need 15 successes and we have 7 so then we need $15-7 = 8$ successes in the new 15 cars in order to satisfy the condition.

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4 years ago

Suppose that X is a random variable with mean 30 and standard deviation 10. Also suppose that Y is a random variable with mean 2

Bas_tet [7]

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3 0

3 years ago

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Anna [14]

Answer:

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