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Kipish [7]
3 years ago
11

Determine whether each ordered pair is a solution of the system.

Mathematics
1 answer:
Stolb23 [73]3 years ago
8 0

According to the system:

5 – 7x + 2y² = -10

1 – 5x – 2y = -22

______________

a) No ; (4, 6) is not a solution to the

system. This point does not touch either equation.

b) No ; (6, 4) is not a solution to the system. This point does not touch either equation.

Solutions:

( \frac{122 - 3 \sqrt{101}}{25}, \frac{ - 7 +3 \sqrt{101}}{10}) ≈ (3.674, 2.315) \\ ( \frac{122  +  3 \sqrt{101}}{25}, \frac{ - 7  - 3 \sqrt{101}}{10}) ≈ (6.086, -3.715)

x = ( 122 ∓ 3√101 ) / 25 ≈ 3.674 or 6.086

y = ( -7 ± 3√101 ) / 10 ≈ 2.315 or -3.715

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When you have the number 81 as your median and you have to find the missing number out of the following 82,87,77,70,80,88
Natali5045456 [20]
Uh, so, you're median is 81 already.

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6 0
3 years ago
X*2+1=10 then x=? Tell me the value of x
Trava [24]

Answer:

<h2>4.5</h2>

Step-by-step explanation:

x \times 2 + 1 = 10

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Hope this helps..

Best regards!!

6 0
3 years ago
Which equation is a function of x? x = 5 x = y squared 9 x squared = y x squared = y squared 16
natita [175]

The equation which is a function of x is x²=y.

Given an equation that is a function of x.

A function may be a relation between a collection of inputs and a collection of permissible outputs with the property that every input is said to precisely one output.

If we input a value of x then we get the output f(x) = y, which is the function of x.

We are given four options out of which we are to pick the one which may be a function of 'x'.

The first option is x=5 in which no term of y is included and its a constant. So, option 1 is not correct.

The second option is x=y²+9 in which y contains a power 2. So, option 2 is not correct.

The third option is x²=y in which y contains power 1. So, option 3 is correct.

The fourth option is x²=y²+16 in which y contains a power 2. So, option 3 is not correct.

Hence, the equation which is a function of x is x²=y.

Learn about functions from here brainly.com/question/16614909

#SPJ4

4 0
2 years ago
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