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Kipish [7]
3 years ago
11

Determine whether each ordered pair is a solution of the system.

Mathematics
1 answer:
Stolb23 [73]3 years ago
8 0

According to the system:

5 – 7x + 2y² = -10

1 – 5x – 2y = -22

______________

a) No ; (4, 6) is not a solution to the

system. This point does not touch either equation.

b) No ; (6, 4) is not a solution to the system. This point does not touch either equation.

Solutions:

( \frac{122 - 3 \sqrt{101}}{25}, \frac{ - 7 +3 \sqrt{101}}{10}) ≈ (3.674, 2.315) \\ ( \frac{122  +  3 \sqrt{101}}{25}, \frac{ - 7  - 3 \sqrt{101}}{10}) ≈ (6.086, -3.715)

x = ( 122 ∓ 3√101 ) / 25 ≈ 3.674 or 6.086

y = ( -7 ± 3√101 ) / 10 ≈ 2.315 or -3.715

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3+7=7+3 is an example of which property
-Dominant- [34]
Commutative because your switching the order
6 0
3 years ago
What’s the slope and y - intercept of this equation ?
Jlenok [28]
Slope 4x and y-intercept is -10 I think I’m positive
8 0
2 years ago
Read 2 more answers
⦟KLJ and ⦟JLM are a linear pair. Find the measures of ⦟KLJ and ⦟JLM.
KATRIN_1 [288]

Answer:

Step-by-step explanation:

6x + 12 + 4x + 8 =  180 {Linear pair}

6x + 4x + 12 + 8 = 180 {Combine like terms}

         10x + 20  = 180   {Subtract 20 from both sides}

              10x =  180 - 20

             10x  = 160    {Divide both sides by 10}

               x = 160/10

                x = 16

m∠KLJ = 6*16 + 12

            = 96 +12

            = 108

m∠JLM = 4*16 + 8

            = 64 + 8

            = 72

8 0
2 years ago
Read 2 more answers
X+5 divided by 3=15 what is the answer?
GREYUIT [131]
All you have to do is solve for x. See the following steps below.

Step 1. Subtract \frac{5}{3} from both sides

X= 15-\frac{5}{3}

Step 2. Simplify 15- \frac{3}{5} to \frac{40}{3}

X= \frac{40}{3}
4 0
3 years ago
Read 2 more answers
a train travels 288km at a uniform speed.if the speed has been 4km per hour more it would have taken one hour less for the same
Lostsunrise [7]

Given:

A train travels 288 km at a uniform speed.

If the speed has been 4 km per hour more it would have taken one hour less for the same journey.

To find:

The initial speed of the train.

Solution:

Let x km/h be the initial speed on the train.

New speed of train = (x+4) km/h

We know that,

Time=\dfrac{Distance}{Speed}

Time taken by the train initially to cover 288 km is \dfrac{288}{x} hours.

New time taken by the train to cover 288 km is \dfrac{288}{x+4} hours.

It is given that If the speed has been 4 km per hour more it would have taken one hour less for the same journey.

\dfrac{288}{x}-\dfrac{288}{x+4}=1

\dfrac{288(x+4)-288x}{x(x+4)}=1

288x+1152-288x=x^2+4x

1152=x^2+4x

0=x^2+4x-1152

Splitting the middle term, we get

x^2+36x-32x-1152=0

x(x+36)-32(x+36)=0

(x+36)(x-32)=0

x=-36,32

We know that the speed cannot be negative. So, the only possible value of x is 32.

Therefore, the speed of the train is 32 km/h.

3 0
2 years ago
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