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Pie
3 years ago
14

Cathy used a probability simulator to pull 3 colored marbles from a bag and flip a coin 50 times. The results are shown in the t

ables below:
Color of
Marble Number of
Times Rolled
Blue
12
Green
18
Yellow
20


Heads Tails
30
20


Using Cathy's simulation, what is the probability of pulling a blue marble and the coin landing tails up?
Mathematics
1 answer:
aliya0001 [1]3 years ago
5 0

Answer:

blue marble 12/50. tails 20/50

Step-by-step explanation:

12/50×20/50 =240/2500= 12/125 =9.6%

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The manufacturing engineers of a renowned pizza brand reduced the manufacturing cost of a pizza delivery box by optimising the s
jekas [21]

Given: A pizza box's volume has been reduced by 25% by flattening the curved side of the box. The dimensions of the box are given.

Required: To determine the angle, the area of the sector of the top surface of the old box design, the area of the top surface of the newly designed box, and the volume, V, of the newly designed box. Also, determine the height of the box, h.

Explanation: The given box is-

If we draw a perpendicular as shown in the figure, the angle is bisected, and the side 24 cm is also bisected as the triangle on the top is an isosceles triangle. This can be easily proved by showing that the smaller triangles on the top face are congruent.

Next, we can use the trigonometric ratio sine to determine the angle as follows-

\begin{gathered} sin\theta=\frac{12}{36} \\ \theta=sin^{-1}(\frac{1}{3}) \\ \theta=19.47\degree \end{gathered}

Thus,

2\theta=38.94\degree

Next, the top of the new box is now a triangle with a base of 24 cm and a height-

\begin{gathered} \text{ Height of triangle}=36cos\theta \\ =36cos(19.47\degree) \\ =33.94\text{ cm} \end{gathered}

Hence, the area is-

\begin{gathered} A=\frac{1}{2}\times24\times33.94 \\ =407.30\text{ cm}^2 \end{gathered}

Now, the old box is a sector with a central angle of 38.94 degrees and a radius of 36 cm. Hence the area of the old box is-

\begin{gathered} A=\frac{\theta}{360}\times\pi r^2 \\  \end{gathered}

Substituting the values as-

\begin{gathered} A=\frac{38.94}{360}\times3.14\times36\times36 \\ =440.18\text{ cm}^2 \end{gathered}

Lastly, the volume of the new box is 25% less than the old box. Hence the volume of the new box is-

\begin{gathered} V=\frac{25}{100}\times3277 \\ =819.25\text{ cm}^3 \end{gathered}

We can determine the height as follows-

\begin{gathered} Vol=Area\times h \\ \Rightarrow h=\frac{Vol}{Area} \end{gathered}

Hence,

\begin{gathered} h=\frac{819.25}{407.30} \\ =2.011\text{ cm} \end{gathered}

Final Answer: A)

2\theta=38.94\degree

B) i) The area of the top of the old box=440.18 sq centimeters.

ii) The area of the top of the new box=407.30 sq centimeters.

C) i) The volume of the new box is 819 cubic centimeters.

ii) h=2.01 cm

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2 years ago
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Answer:

1 is 40/7

Step-by-step explanation:

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