The numerical sum of the degree measures of m ∠DEA and m ∠AEF and m ∠DEF is 360°; The numerical measures of the angles is,
m ∠DEA = 56°
m ∠AEF = 158°
m ∠DEF = 146°
Based on the given data,
m ∠DEA= x + 30,
m ∠AEF= x + 132, and
m ∠DEF= 146 degrees
If the sum of two linear angles is 360° then, they are known as supplementary angles.
∠A + ∠B + ∠C = 360°, (∠A and ∠B and ∠C are linear angles.)
So,
We can write,
m ∠AEF + m ∠DEA + m ∠DEF = 360°
( x + 132) + (x + 30) + 146 = 360°
x + 30 + x + 132 + 146 = 360°
2x + 308 = 360°
2x = 360° - 308
x = 52/2
x =26
Now, we will substitute the value of x = 26° in the ∠DEA and ∠AEF, hence we get:
m ∠DEA = x + 30
m ∠DEA = 26 + 30
m ∠DEA = 56 degrees
Also,
m ∠AEF = x + 132
m ∠AEF = 26 + 132
m ∠AEF = 158
Hence,
m ∠DEA + m ∠AEF + m ∠DEF = 360°
56 + 158 + 146 = 360°
360° = 360°
Therefore,
Therefore, the numerical sum of the degree measures of m ∠DEA and m ∠AEF and m ∠DEF is 360°; The numerical measures of the angles is,
m ∠DEA = 56°
m ∠AEF = 158°
m ∠DEF = 146°
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Answer:
option 3, double the height and with of original bottle
Answer:
24
Step-by-step explanation:
subract 4 each time
Answer:
1000 balls
(there are infinitely many solutions to this question; you can scale up 1000, use a different total, etc.)
Step-by-step explanation:
there are, of course, multiple possible numbers,
but the easiest way is to go with 1000, because we can say 375 / 1000 and 400 / 1000
(0.4 + 0.275 + 0.225 = 1)
400 out of 1000 balls are red (400/1000 = 4/10 = 0.4)
375 out of 1000 balls are green (375/1000 = 3.75/10 = 0.375)
225 out of 1000 balls are yellow (225/1000 = 2.25/10 = 0.225)
the question never gave detail as to if the answer should be the <em>lowest</em><em> </em>number of possible balls, so this value is possible.
So, a possible number of balls in this bag is 1000.
From Newton’s Second Law of Motion, the force needed to accelerate a moving object of mass m at acceleration a is given by ;
F = ma
In this case, m = 5kg, a = 6m/s^2 and we want to find F
F = 5 x 6
F = 30N
Therefore, a force of 30N is needed to accelerate a 5kg object at 6m/s^2.
