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3 years ago

Pleaseeeeeeee help 32 points

Mathematics

1 answer:

zlopas [31]3 years ago

8 0

Find out the length of each side. For the slanty sides, you can do this by using the formula

$d = \sqrt{(y2-y1)^{2} +(x2-x1)^{2} }$

For the straight sides (like the one on the bottom and the one on the left), just use simple subtraction.

Add up all 4 sides and you get the perimeter. You should get 20, 15, $5\sqrt{5}$ and $5\sqrt{26}$ . The total is 35 + $5(\sqrt{26} +\sqrt{5} )$ .

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A box has a total surface area of $100.$ The length of the box is equal to twice its width, as well as equal to $3$ less than it

CaHeK987 [17]

Answer:

Formula: width x depth x height

Step-by-step explanation:

times 100 and 3. As we know that the formula for a box is width x depth x height.

We need to measure the box from all side so 4 sides. so times the 2 number by 2 cause there is 4 sides each.

Hope this helps

7 0

3 years ago

the length of one side of a square field is represented by the expression 3 - 7 x what is an expression for the perimeter of the

iragen [17]

4(3-7x). Since there are 4 sides in a square, you multiply one length by 4 to get the perimeter. 4(3-7x) simplifys to 12-28x.

3 0

3 years ago

1) Let f(x)=6x+6/x. Find the open intervals on which f is increasing (decreasing). Then determine the x-coordinates of all relat

brilliants [131]

Answer:

1) increasing on (-∞,-1] ∪ [1,∞), decreasing on [-1,0) ∪ (0,1]

$x = -1$ is local maximum, $x = 1$ is local minimum

2) increasing on [1,∞), decreasing on (-∞,0) ∪ (0,1]

$x = 1$ is absolute minimum

3) increasing on (-∞,0] ∪ [8,∞), decreasing on [0,4) ∪ (4,8]

$x = 0$ is local maximum, $x = 8$ is local minimum

4) increasing on [2,∞), decreasing on (-∞,2]

$x = 2$ is absolute minimum

5) increasing on the interval (0,4/9], decreasing on the interval [4/9,∞)

$x = 0$ is local minimum, $x = 4/9$ is absolute maximum

Step-by-step explanation:

To find minima and maxima the of the function, we must take the derivative and equalize it to zero to find the roots.

1) $f(x) = 6x + 6/x$

$f\prime(x) = 6 - 6/x^2 = 0$ and $x \neq 0$

So, the roots are $x = -1$ and $x = 1$

The function is increasing on the interval (-∞,-1] ∪ [1,∞)

The function is decreasing on the interval [-1,0) ∪ (0,1]

$x = -1$ is local maximum, $x = 1$ is local minimum.

2) $f(x)=6-4/x+2/x^2$

$f\prime(x)=4/x^2-4/x^3=0$ and $x \neq 0$

So the root is $x = 1$

The function is increasing on the interval [1,∞)

The function is decreasing on the interval (-∞,0) ∪ (0,1]

$x = 1$ is absolute minimum.

3) $f(x) = 8x^2/(x-4)$

$f\prime(x) = (8x^2-64x)/(x-4)^2=0$ and $x \neq 4$

So the roots are $x = 0$ and $x = 8$

The function is increasing on the interval (-∞,0] ∪ [8,∞)

The function is decreasing on the interval [0,4) ∪ (4,8]

$x = 0$ is local maximum, $x = 8$ is local minimum.

4) $f(x)=6(x-2)^{2/3} +4=0$

$f\prime(x) = 4/(x-2)^{1/3}$ has no solution and $x = 2$ is crtitical point.

The function is increasing on the interval [2,∞)

The function is decreasing on the interval (-∞,2]

$x = 2$ is absolute minimum.

5) $f(x)=8\sqrt x - 6x$ for $x>0$

$f\prime(x) = (4/\sqrt x)-6 = 0$

So the root is $x = 4/9$

The function is increasing on the interval (0,4/9]

The function is decreasing on the interval [4/9,∞)

$x = 0$ is local minimum, $x = 4/9$ is absolute maximum.

5 0

3 years ago

There were 94,172 people at a football game, which digit is in the thousand place in this number

Simora [160]

Answer: 4

Step-by-step explanation:

94,172

ten thousands, thousands, hundreds, tens, ones

According to the list of places, 4 is the thousand place in 94,172.

Hope this helps!! :)

Please let me know if you have any question

6 0

4 years ago

Read 2 more answers

The area of a rectangular box are 100in squared, 90 in squared, and 40 in squared. What is the volume of the box?

topjm [15]

L*W*H, 100*90*40 = 360000

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3 years ago