Express sin 6x-sin 2x in product form.

1 answer:

7 0

Answer:

Step-by-step explanation:

sin C-sin D=2cos ((C+D)/2)sin ((C-D)/2)

$sin ~6x-sin ~2x=2cos ~\frac{6x+2x}{2} sin ~\frac{6x-2x}{2} \\=2 ~cos~4x~sin~2x$

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Express sin 6x-sin 2x in product form.​