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r-ruslan [8.4K]

2 years ago

10

Without subtracting 8.5-4.6 for what digit will be in the hundreds place

1 answer:

zvonat [6]2 years ago

6 0

There is no number in the hundreds place

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The measure of angle A is 4 degrees greater than the measure of angle B. The two angles are complementary. Find the measure for

Elenna [48]

Sorry but i only know the answer for the 1st question.
--------------------------
If the angles are complementary they measure 90°.
1st find half of 90
which is 45.
Find 4 more than 45.
which is 49°
then subtract 90-49=41
so the measurement of the 2 angles are
49 and 41
Hope it helps!!

7 0

3 years ago

2x= -10 what is x??????

Reptile [31]

The correct answer is X = -5

5 0

2 years ago

PLEASE HELPPP i would really appreciate it :)

qaws [65]

Answer:

Y = - 12.55X1 + 276.52

Step-by-step explanation:

Given the data:

Age of child :(X) : 4, 6, 10, 13, 14, 17

Time (seconds) (Y) : 230, 205, 132, 119, 108, 62

Using technology, the linear regression equation obtained using the data Given is :

Y = - 12.55X1 + 276.52

Where :

Slope = - 12.55

Intercept = 276.52

This also indicates that a negative slope is present and hence a negative relationship between age of Child and time in seconds.

3 0

2 years ago

Jim's cat, c, weighs 7 pounds. His dog weighs six times plus 3 pounds. more than his cat. Which equation represent the dogs weig

Alex17521 [72]

C =7
d is 6 times c+3
d=6c+3

d=6d+3 is equation
(if you sub, you would get 45 is weight)

5 0

3 years ago

Problem PageQuestion Calcium levels in people are normally distributed with a mean of mg/dL and a standard deviation of mg/dL. I

SIZIF [17.4K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The calcium level that is the borderline between low calcium levels and those not considered low is $c = 8.68$

Step-by-step explanation:

From the question we are told that

The mean is $\mu = 9.5\ mg/dL$

The standard deviation $\sigma = 0.5 \ mg/dL$

The proportion of the population with low calcium level is $p =$ 5% = 0.05

Let X be a X random calcium level

Now the P(X < c) = 0.05

Here P denotes probability

c is population with calcium level at the borderline

Since the calcium level is normally distributed the z-value is evaluated as

$P(Z < \frac{c - \mu}{\sigma } ) = 0.05$

The critical value for 0.05 from the standard normal distribution table is

$t_{0.05} = -1.645$

=> $\frac{c - \mu}{\sigma } = -1.645$

substituting values

$\frac{c - 9.5}{0.5 } = -1.645$

=> $c - 9.5 = -0.8225$

=> $c = 8.68$

6 0

2 years ago