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2 years ago

Please help me with this I will name branlist

Mathematics

2 answers:

otez555 [7]2 years ago

8 0

I wish I knew but same profile pic pog

finlep [7]2 years ago

4 0

Answer:

IT's -3.6 & 14.4 so D is the correct answer

Step-by-step explanation:

x= -3.6 y= 14.4

HOW I SOLVED IT

-3.6 x 3 = -10.8 2 x 14.4 = 28.8 - 10.8 = 18 so correct since it must equal to 18

-2/3 x -3.6 =2.4 + 12 = 14.4 so correct since y = 14.4

Brainilest would be appreciated :)

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You are driving to visit a friend in another state who lives 440 miles away. You are driving 55 miles per hour and have already

Veseljchak [2.6K]

440 miles - 275 miles = 165 miles

165 + 275 = 440

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3 years ago

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you currently have 24 credit hours and a 2.8 gpa you need a 3.0 gpa to get into the college. if you are taking a 16 credit hours

Juliette [100K]

Answer:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

Step-by-step explanation:

For this case we know that the currently mean is 2.8 and is given by:

$\bar X = \frac{\sum_{i=1}^n w_i *X_i }{24} = 2.8$

Where $w_i$ represent the number of credits and $X_i$ the grade for each subject. From this case we can find the following sum:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

6 0

2 years ago

Giselle spent 7/10 of her money on a book and 10/100 of her money on food. What fraction of her money did she spend altogether?

aleksklad [387]

Answer:

80/100 or 80%

Step-by-step explanation:

7/10 = 70/100

70/100 + 10/100 = 80/100

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2 years ago

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k0ka [10]

k-3+3<5+3 is the explanation and the answer is k<8

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2 years ago

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Masja [62]

Answer:

Step-by-step explanation:

i think it is B

4 0

2 years ago

Please help me with this I will name branlist​

Please help me with this I will name branlist