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MrRa [10]
3 years ago
10

What is (y-10)(4y+2)?

Mathematics
2 answers:
AleksandrR [38]3 years ago
8 0

Answer:

4y²−38y−20

Step-by-step explanation:

(y−10)(4y+2)

=(y+−10)(4y+2)

=(y)(4y)+(y)(2)+(−10)(4y)+(−10)(2)

=4y²+2y−40y−20

=4y²−38y−20

please mark me brainliest!

ryzh [129]3 years ago
3 0

Answer:

Step-by-step explanation:

(y-10)(4y+2)\\ (a+b)(c+d)=ac+ad+bc+bd\\4y^2+2y-40y-20\\4y^2 -38y -20

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(5⁴)²?????? <br><br><br>A:5⁶<br>B:5⁸<br>C:20²<br>D:25⁸​
ArbitrLikvidat [17]

Answer:c 20

Step-by-step explanation:

4 0
3 years ago
(ANSWER ASAP) The table represents the multiplication of two binomials. What is the value of A?
PSYCHO15rus [73]
<h3>The value of A will be -3x^2 </h3>

By observing the table it can be concluded that the value of A must be equal to 3x × (-x)

So, the value will be -3x^2

4 0
2 years ago
This is my last question it’s due at midnight can I please get help in a hurry
Sophie [7]

N = 9

explanation: If you tilt triangle FGH to where it matches triangle PQR, 9 is matched with N.

more help:

Q = G

10.5 = 7

P = F

H = R

4 = 6

9 = N

5 0
2 years ago
A family has two cars. The first car has a fuel efficiency of 15 miles per gallon of gas and the second has a fuel efficiency of
professor190 [17]

The fuel consumption of each of the cars during the week are as follows;

  • The first car consumes <u>20 gallons of fuel</u>.
  • The second car consumes <u>30 gallons of fuel</u>.

Reasons:

Fuel efficiency of the first car = 15 miles per  gallon

Fuel efficiency of the second car = 35 miles per gallon

Combined distance traveled by the two cars in a week = 1,350 miles

The total gas consumption during the week = 50 gallons

Let <em>x</em> represent the number of gallons consumed by the first car, and let <em>y</em>

represent the number of gallons consumed by the second car, we get the

following system of simultaneous equations;

  • 15·x + 35·y = 1,350...(1)
  • x + y = 50...(2)

Therefore;

y = 50 - x

Which gives;

15·x + 35 × (50 - x) = 1,350

15·x + 1,750 - 35·x = 1,350

1,750 - 1,350 = 35·x - 15·x = 20·x

400 = 20·x

x = 400 ÷ 20 = 20

  • The number of gallons consumed by the first car, x = <u>20 gallons</u>

From equation (2), we have;

x + y = 50

y = 50 - x

Therefore;

y = 50 - 20 = 30

  • The number of gallons consumed by the second car, y = <u>30 gallons</u>

Learn more about word problems that lead to simultaneous equations here:

brainly.com/question/1717365

6 0
2 years ago
Heeelpppppppppppppppppppppppppppppppp
Vinil7 [7]

Answer:

1,512

Step-by-step explanation:

I got you ok so, you just multiply all the numbers. and when there is that much numbers you are gonna be in the a thousands. use a calculator easy!

3 0
3 years ago
Read 2 more answers
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