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elena55 [62]
3 years ago
9

What is the equation of the axis of symmetry of the graph of y=ax^2+bx+c

Mathematics
2 answers:
elena-s [515]3 years ago
8 0
That would be x=-b/(2a)
that sounds crazy but it works

for all y=ax²+bx+c, the axis of symmetry is \frac{-b}{2a}


Phantasy [73]3 years ago
4 0

Answer:

x=-\frac{b}{2a}

Step-by-step explanation:

we know that

The quadratic equation y=ax^{2}+bx+c is a vertical parabola

The axis of symmetry in a vertical parabola is a vertical line

The equation of the axis of symmetry in a vertical parabola is equal to the x-coordinate of the vertex

The x-coordinate of the vertex is equal to the formula

x=-\frac{b}{2a}

therefore

the equation of the axis of symmetry is equal to x=-\frac{b}{2a}

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nata0808 [166]

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6 0
3 years ago
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Write a rule for a geometric sequence that has a 1 as its first term and a common ratio of -4. what is the seventh term of this
ivann1987 [24]

I hope first term is 1.

Hope this is your question, if not I think you will, still be able to

find an answer of your question based on this solution.

The formula for general term of a geometric sequence is,

a_{n} =a_{1} *r^{n-1}

Where, first term: a_{1} =1 and common ratio: r = -4.

So, first step is to plug in the values of a1 and r in the above formula to get the rule of this geometric sequence. Hence,

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So, the rule of the geometric sequence is a_{n} =4^{n-1}.

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a_{7} =4^{7-1}

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= 4096

Hope this helps you!.

6 0
3 years ago
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Natalka [10]

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Have a great day

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