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zubka84 [21]
3 years ago
10

Please help out !!!!!!!!

Mathematics
1 answer:
Sergio [31]3 years ago
5 0

Answer: D

Step-by-step explanation:

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Suppose that the revenue function for a certain product is given by R(x) = 17(2x + 1)−1 + 34x − 17 where x is in thousands of un
REY [17]

Answer:

Step-by-step explanation:

Given that:

R(x) = \frac{17}{2x+1} + 34x − 17

As we know that derivative of revenue function is marginal revenue function .

We will use following rules of derivative

=> dR/ dx = \frac{-17*2}{(2x+1)^{2} } + 34

=> R' (x) =   \frac{-34}{(2x+1)^{2} } + 34

=> R '(2000) =  \frac{-34}{(2*2000+1)^{2} } + 34 = 34

The revenue when 2000 units are sold is:

R(2000) = \frac{17}{2*2000+1} + 34*2000 − 17 = $69,783

3 0
3 years ago
Here you go this is the full question please help
hammer [34]
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2 years ago
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These triangles are congruent by what theorem? <br>ASA or AAS​
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Angle angle side ( AAS)
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2 years ago
On Naomi's cell phone plan, the amount she pays each month for international text messages is proportional to the number of inte
Lostsunrise [7]

A) The constant of proportionality in this proportional relationship is k = \frac{y}{x}

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<h3><u>Solution:</u></h3>

Given that,

The amount Naomi pays each month for international text messages is proportional to the number of international texts she sends that month

Therefore,

This is a direct variation proportion

\text{ amount Naomi pays each month } \propto \text{ number of international texts she sends that month}

Let "y" be the amount that Naomi pays each month

Let "x" be the number of international texts she sends that month

Therefore,

y \propto x

y = kx -------- eqn 1

Where, "k" is the constant of proportionality

Thus the constant of proportionality in this proportional relationship is:

k = \frac{y}{x}

<em><u>Last month, she paid $3.20 for 16 international texts</u></em>

Therefore,

y = 3.20

x = 16

Thus from eqn 1,

3.20 = k \times 16\\\\k = \frac{3.20}{16}\\\\k = 0.2

Substitute k = 0.2 in eqn 1

y = 0.2x

The equation would then be y = 0.2x

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3 years ago
Greg is designing the clock face for a homemade clock. Using the center of the clock face as the origin, he places the label 12
Viktor [21]
Given:
Origin of the clock face (0,0)
label 12 point (0,5)

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Label 6 should be placed on the point (0,-5). The point of label 12 should be reflected across the x-axis and labeled as 6 of the clock face.
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