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zubka84 [21]
2 years ago
10

Please help out !!!!!!!!

Mathematics
1 answer:
Sergio [31]2 years ago
5 0

Answer: D

Step-by-step explanation:

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Solve for y. 6 = 2(y + 2) <br> A) 6<br> B) 1 <br> C) 8<br> D) 2
tankabanditka [31]
The answer is B.

6 = 2 (y + 2)

y = 1
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3 years ago
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Given the function defined in the table below, find the average rate of
AURORKA [14]

Answer:

Average rate of change = \frac{2}{5}

Step-by-step explanation:

Average rate of change of a function 'f' in the interval a ≤ x ≤ b is given by,

Average rate of change = \frac{f(b)-f(a)}{b-a}

We have to find the average rate of change in the interval 20 ≤ x ≤ 65

From the table attached,

f(65) = 32

f(20) = 14

Average rate of change = \frac{32-14}{65-20}

                                        = \frac{18}{45}

                                        = \frac{2}{5}

Therefore, average rate of change in the given interval is \frac{2}{5} .

7 0
3 years ago
2. Angelica reflects ABCDE over the yaxis and translates to Does her transformed figure match A'B' C D'Ef not describe honored f
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Step-by-step explanation:

5 0
3 years ago
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If $3,000,000 is invested at 6% interest compounded continuously, how much
g100num [7]

Answer:

  $24,498,509.74

Step-by-step explanation:

The formula for the value as a function of time is ...

  V(t) = P·e^(rt)

Filling in the numbers and doing the arithmetic, we have ...

  V(35) = 3,000,000·e^(0.06·35) ≈ 24,498,509.74

Compounded continuously for 35 years, the investment will be worth $24,498,509.74.

3 0
3 years ago
Someone help me please
galben [10]

Answer:

∛27 = 3

Step-by-step explanation:

A radical is simply a fractional exponent: a^{(\frac{m}{n})} = \sqrt[n]{a^{m} }

Hence, ∛27 = 27^{(\frac{1}{3})}

Since 27 = 3³, then:

You could rewrite ∛27 as ∛(3)³.

\sqrt[3]{3^{(3)} } = 3^{[(3)*(\frac{1}{3})]}

Multiplying the fractional exponents (3 × 1/3) will result in 1 (because 3 is the <u><em>multiplicative inverse</em></u> of 1/3). The multiplicative inverse of a number is defined as a number which when multiplied by the original number gives the product as 1.

Therefore, ∛27 = 3.

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2 years ago
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