There are 3 ways of solving a simultaneous problem, substitution method, elimination method and Gauss-Jordan method. I'm gonna use the substitution method since it's easier and i think it would suit your level more.

First let's try solving for y since it's easier to start with.

Firstly we have to find an equation for x:

$x-2y=2\\x-2y+2y=2+2y\\x=2+2y$

Great, now we can use the substitution method to find the value of y using the first equation:

$2x+3y=11\\2(2+2y)+3y=11\\4+4y+3y=11\\7y=7\\y=1$

Now we know that y=1 we can solve the first equation we made:

$x=2+2y\\x=2+2(1)\\x=4$

And the answer is $x=4 , y= 1\\(4,1)$

Double check:

$2x+3y=11\\2(4)+3(1)=11\\8+3=11\\11=11\\\\x-2y=2\\(4)-2(1)=2\\2=2$

And that's our final answer! (4,1)

7 0

3 years ago

Find the remainder when f(x) is divided by (x - k) <br> f(x) = 5x4 + 8x3 + 4x2 - 5x + 67; k = 2

yan [13]

It is to be solved by reminder thorem
f(x)/(x-k) will have reminder f(k),
so, f(2) = 5*(2^4) + 8 *(2^3) +4* (2^2) -5(2) +67

=5*16 + 8*8 +4*4 -5*2 +67
=80 + 64 + 16 -10 +67

= 217

8 0

2 years ago

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