1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Luda [366]
3 years ago
9

To win a local billiards tournament, all Jeanette has left to do is drop the 9-ball. Because of the other balls on the table (no

t shown), her only realistic shot on this turn is to bounce the ball off both sides of the table as shown. Use the information in the image to answer the questions below. Lines AB and CH are parallel, and the near side of the table is parallel to the far side.
a. What other angle measures can we be sure about? Explain your reasoning.
b. Identify the sets of congruent angles. Explain your conclusions.
c. Identify all the sets of alternate interior angles you can envision. Explain.
d. Identify all the sets of corresponding angles. Explain.

Mathematics
1 answer:
alukav5142 [94]3 years ago
7 0

Answer:

Here's what I get.

Step-by-step explanation:

Assume the diagram is like the one below.

Segments AB, BC, and CH are transversals to the sides of the pool table.

BC is also a transversal to AB and CH.

a. Angles we can be sure about

∠ABC — interior opposite angles of transversal BC

∠CBH — interior opposite angles of transversal BC

∠BHC — interior angles of triangle BHC

∠ABK — alternate exterior angles of transversal BC

∠CHG — complementary to ∠CGH

b. Sets of congruent angles

∠ABC ≅ ∠BCH = 66° — interior opposite angles of transversal BC

∠CBH ≅ ∠BCE = 57° — interior opposite angles of transversal BC

∠BHC ≅ ∠GCH = 57° — interior opposite angles of transversal CH

∠ABK ≅ ∠GCH = 57° — alternate exterior angles of transversal BC

One set of congruent angles is {∠ABC, ∠BCH}

Another set is {∠ABK, ∠BCE, ∠BHC, ∠CBH, ∠GCH}

c.  Alternate interior angles

Alternate interior angles are a pair of angles on the inner sides of the parallel lines but on opposite sides of the transversal.

The sets of alternate interior angles are {∠ABC, ∠BCH}, {∠ ABC, ∠BCD} {∠BCE,  ∠CBH}, {∠CHJ, ∠GCH}

d. Corresponding angles

Corresponding angles are a pair of angles on the same side of parallel lines and on the same side of the transversal.

The diagram has no corresponding angles.

You might be interested in
2d+32, when d=8, equals,
Luba_88 [7]

Answer:

Substitute the value of the variable into the equation and simplify.

48

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is the length of the missing leg? Hint: Use the Pythagorean Theorem
yaroslaw [1]
<h3>♫ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Pythagoras' theorem:

b^2 = c^2 - a^2

Substitute in the values:

b^2 = 13^2 - 12^2

b^2 = 25

Square root it

b = 5km

The answer is option B. 5km

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

<u></u>

↬ ʜᴀɴɴᴀʜ ♡

6 0
4 years ago
The curved part of this figures is a semicircle.
Dennis_Churaev [7]
The answer is <span>14+8.125π</span><span> units².</span>
6 0
3 years ago
Read 2 more answers
On another map the distance between saugerties and kingston is 2 inches. Whar would tge distance from saugerties to catskill be
Mariana [72]

The question is incomplete. The map is attached as a photo and here is the complete question:

a. What is the actual distance between Saugerties and

Kingston? ___________________________

b. Catskill is 15 miles from Saugerties. What would the

distance on the map be? ___________________________

c. On another map, the distance between Saugerties and

Kingston is 2 inches. What would the distance from Saugerties to

Catskill be on this map? __________________

Since you have asked the answer for part (c) only, here is the answer:

Answer:

<u>The distance from Saugerties to Catskill would be </u><u>3 inches</u><u> on this map.</u>

Step-by-step explanation:

On the given map, the distance between Saugerties and Kingston is 4 inches and the scale is <u>1 inch = 2.5 miles.</u>

To calculate the actual distance in miles between Saugerties and Kingston, consider the given scale:

1 inch ---------- 2.5 miles

4 inches ------ x miles

Cross multiplying:

1x = 2.5 x 4

x = 10 miles

The actual distance between Saugerties and Kingston is 10 miles.

On another map, the distance between Saugerties and Kingston is 2 inches. Which means the scale is 2 inches = 10 miles. So 1 inch = 10/2 = 5 miles

The scale on the other map is 1 inch = 5 miles.

Catskill is 15 miles from Saugerties (given in the previous part). So on the map:

1 inch -------- 5 miles

y inch ------- 15 miles

Cross multiplying:

15 = 5y

y = 15/5

<u>y = 3 inches.</u>

The distance from Saugerties to Catskill would be 3 inches on this map.

7 0
3 years ago
A student's grades in the three tests in College Algebra are 85, 60, and 69. a) How many points does the student need on the fin
Anastaziya [24]

Answer:

(a) The student need 82 points on the final to average 74.

(b) The student must score 41 points on the final, assuming that the final carries double the weight.

Step-by-step explanation:

We are given that a student's grades in the three tests in College Algebra are 85, 60, and 69.

As we know that the formula for calculating the average of numbers is given by;

          Average (Mean)  =  \frac{\text{Sum of all values}}{\text{Number of observations}}

(a) Let the points student need on the final test to average 74 be 'x'.

So, Average of all four test  =  \frac{85+60+69+x}{4}

                     74 = \frac{85+60+69+x}{4}

                     74 = \frac{214+x}{4}

                     214+x =74 \times 4

                      x = 296-214

                        x=82

Hence, the student needs 82 points on the final to average 74.

(b) It is given that the final carries double the weight, this means that let the points student need on the final test to average 74 be '2x'.

So, Average of all four test  =  \frac{85+60+69+2x}{4}

                     74 = \frac{85+60+69+2x}{4}

                     74 = \frac{214+2x}{4}

                     214+2x =74 \times 4

                      2x = 296-214

                        x=\frac{82}{2} = 41

Hence, the student must score on the final 41 points, assuming that the final carries double the weight.

7 0
3 years ago
Other questions:
  • Name the algebraic property demonstrated in the example below x.y.z=y.x.z
    10·2 answers
  • Find the product of (x-4) (x+5)
    15·2 answers
  • I need the answer for B
    11·2 answers
  • What's the solution for x? 4+x+2-2x=5
    7·1 answer
  • Help me please it’s hard
    10·2 answers
  • In this triangle, what is the value of x?
    8·2 answers
  • A repairman charges $40.50 per hour. this can be written as $40.50x.evaluate this expression if he works for 5 hours.
    8·2 answers
  • Mo has some sweets. He shares them out between x of his friends in 2 different wys. 7 sweets each with 2 leftover or 6 sweets ea
    8·1 answer
  • Help me please do this
    11·2 answers
  • Find the perimeter of image below. 42 square units, 52 square units, 56 square units, 44 square units
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!