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3 years ago

Which diagram correctly shows the construction used to bisect AB

Mathematics

1 answer:

Shtirlitz [24]3 years ago

3 0

The correct answer would be the first one.

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1.Solve the differential equation dy/dx= y^2/x^3 for y=f(x) with the condition y(1) = 1.

Elza [17]

This ODE is separable, so you can write

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y^2}{x^3}\iff\dfrac{\mathrm dy}{y^2}=\dfrac{\mathrm dx}{x^3}$

Integrating both sides gives

$-\dfrac1y=-\dfrac1{2x^2}+C$

and given the initial condition $y(1)=1$ , you have

$-\dfrac11=-\dfrac1{2(1)^2}+C\implies C=-\dfrac12$

so that the solution is

$-\dfrac1y=-\dfrac1{2x^2}-\dfrac12\implies y=\dfrac1{\frac1{2x^2}+\frac12}=\dfrac{2x^2}{1+x^2}$

4 0

4 years ago

3. Rhombus KLMN with vertices K(-3, 2), L(1, 4),<br> and N(-5, -2): (x,y) → (x+2, y-5)

Art [367]

The translated vertices of the rhombus are: K(-1,-3), L(3,-1), M(1,-5) and N(-3,-7)

The rhombus is a parallelogram which has all sides equal. the diagonals of a rhombus bisect at right angles. the difference between a rhombus and a square is that none of the angles of a rhombus are 90°.

To translate a figure with given co-ordinates into another figure with a particular translation we simply add or subtract the given values from the coordinates of the available points.

Given co-ordinates of Rhombus are K(-3, 2),L(1, 4),M(-1 ,0)and N(-5, -2).

The translation is given as (x,y) → (x+2, y-5)

So we calculate the coordinates as:

The translated co-ordinate K(-3, 2)→ K'(-1,-3)

The translated co-ordinate L(1, 4)→ L'(3,-1)

The translated co-ordinate M(-1 ,0)→ M'(1,-5)

The translated co-ordinate N(-5, -2)→ N'(-3,-7)

Hence the co-ordinates of rhombus translated by (x,y) → (x+2, y-5) are K(-1,-3), L(3,-1), M(1,-5) and N(-3,-7).

To learn more about Rhombus visit:

brainly.com/question/27870968

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6 0

2 years ago

I need some help! Will give brainliest!!!

frosja888 [35]

Answer:

Positive 7 on the line pointing up (y axis) is where you start (where your first dot goes when graphing). Then down two and right one. (Your second dot will end up on (5,1))

Step-by-step explanation:

4 0

3 years ago

The hypotenuse of a right triangle measures 2 square root 15 centimeters and its shorter leg measures 2 square root 6

disa [49]

Answer:

50.8°

Step-by-step explanation:

The mnemonic SOH CAH TOA is intended to remind you of the relationship between side lengths and trig functions for a right triangle. Here, you are given the short side and the hypotenuse, and asked for the largest acute angle.

The short side is adjacent to the largest acute angle, so the relevant relation is ...

Cos = Adjacent/Hypotenuse

cos(β) = (2√6)/(2√15) = √0.4

The angle measure is found using the inverse cosine function:

β = arccos(√0.4) ≈ 50.8°

The larger acute angle is about 50.8°.

8 0

2 years ago

ANSWER QUICK IF POSSIBLE - I GIVE BRAINLYEST

Kitty [74]

The answer would be B

6 0

3 years ago