72 is the minimum grade he must get on the last test in order to have an average of 77.
<u>Step-by-step explanation:</u>
The grades of a student are given 72,91,78,72 and the grade of his last test is not given.
- You have to find the minimum grade the student shall get, so that the student average must be 77.
- The four grades are already given. Therefore, we need to find only the fifth grade.
The term average is defined as the sum of all the data in a set divided by the number of data in a set.
Here, the number of data is 5. (Because the students has 4 grades plus one grade for his last test).
The average he should get is 77.
Average = Sum of all grades / number of grades
Let, 'x' be the grade of the last test.
⇒ 77 = (72+91+78+72+x) / 5
⇒ 77 = (313+x) / 5
⇒ 385 = 313 + x
⇒ x = 385 - 313
⇒ x = 72
The minimum grade he must get on the last test is 72.
Find all the zeros of the polynomial, and arrange the zeros in increasing order. ...
Plot those numbers on the number line as open or closed points based upon the original inequality symbol.
Choose a test value in each interval to see if the interval satisfies the inequality or not.
Answer:do h just want answer or explanation
Step-by-step explanation:?
22 centimeters
242 ( area ) divided by 11( width) =22 ( length)
Sample space ={6y+11b+15g+3bk} = 35 elements
number of black rings=3
probability (black ring) =3/35=0.085
