Complete Question:
Assume that an array of Integers named a that contains exactly five elements has been declared and initialized. In addition, an int variable j has also been declared and initialized to a value somewhere between 0 and 3.
Write a single statement that assigns a new value to the element of the array indexed by j. This new value should be equal to twice the value stored in the next element of the array (i.e. the element after the element indexed by j ). Do not modify any other elements of the array!
Answer:
a[j] = 2 * a[j+1];
Explanation:
Since the array is named a and its indexes are referenced by the variable j
it means the elements of the array will be a[j] for (j=0; j=1;j=2).
The first element in the array (j=0) will be a[0], second element will be a[1] and so on.
The statement a[j] = 2 * a[j+1]; assigns a new value to the element of the array indexed by j, the value is equal to twice the value stored in the next element of the array (j+1).
Answer:
click on your profile and im pretty sure it says privacy information and click on that and from there it will ask you for your information
Explanation:
Answer:
Condition-controlled loop
Explanation:
be happy
Answer:
True
Explanation:
The ESP register acts as an indirect operand pointing to the top of the stack at any time.
Stack grows downwards from high memory when a program adds to the stack. However, when items are removed from the stack, it shrinks upwards from low to high memory.
The assembler reduces the stack pointer(ESP) register by 2, when a word value is pushed on to the stack. On the other hand, the assembler increases the stack pointer by 2 when a word value is popped off.
The assembler decreases or increases the ESP register by 4 when a double word value is pushed or popped off the stack respectively. Therefore the ESP register changes in multiples of 4.
