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algol13
3 years ago
8

Samantha was calculating a mathematical formula on an electronic spreadsheet. She used multiple values to recalculate the formul

a. Where will the CPU store data for easy access and quick retrieval during these computations? read-only memory random-access memory hard disk compact disk
Computers and Technology
2 answers:
Bezzdna [24]3 years ago
5 0
<span>Random access memory. This problem requires you to know what the different types of memory are and their relative advantages and disadvantages. Let's look at them and see why 3 are wrong and one is correct. read-only memory: Otherwise known as ROM, this type of memory stores code that can't be over written. Used frequently for constant lookup values and boot code. Since it can't be written to by normal programs, it can't hold temporary values for Samantha. So this is the wrong choice. random-access memory: Otherwise known as RAM, this type of memory is used to store temporary values and program code. It is quite fast to access and most the immediately required variables and program code is stored here. It can both be written to and read from. This is the correct answer. hard disk: This is permanent long term readable and writable memory. It will retain its contents even while powered off. But accessing it is slow. Where the contents of RAM can be accessed in nanoseconds, hard disk takes milliseconds to seconds to access (millions to billions of times slower than RAM). Because it's slow, this is not the correct answer. But it's likely that Samantha will save her spreadsheet to hard disk when she's finished working with it so she can retrieve the spreadsheet later to work on again. compact disk: This is sort of the ROM equivalent to the hard disk. The data stored on a compact disk can not be over written. One way of describing the storage on a compact disk is "Write Once, Read many times". In most cases it's even slower than the hard disk. But can be useful for archiving information or making backups of the data on your computer.</span>
LenKa [72]3 years ago
5 0

Answer: RAM

Explanation:

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Answer:

  1. def getCharacterForward(char, key):  
  2.    charList = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
  3.    if(len(char) > 1):
  4.        return None  
  5.    elif(not isinstance(key, int)):
  6.        return -1
  7.    else:
  8.        index = charList.find(char)
  9.        if(index + key <= 25):
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  11.        else:
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Explanation:

Firstly, define a charList that includes all uppercase alphabets (Line 2). We presume this program will only handle uppercase characters.

Follow the question requirement and define necessary input validation such as checking if the char is a single character (Line 4). We can do the validation by checking if the length of the char is more than 1, if so, this is not a single character and should return None (Line 5). Next, validate the key by using isinstance function to see if this is an integer. If this is not an integer return -1 (Line 6 - 7).

Otherwise, the program will proceed to find the index of char in the charList using find method (Line 9). Next, we can add the key to index and use the result value to get forwarded character from the charList and return it as output (Line 11).

However, we need to deal a situation that the char is found at close end of the charList and the forward key steps will be out of range of alphabet list. For example the char is X and the key is 4, the four steps forward will result in out of range error. To handle this situation, we can move the last two forward steps from the starting point of the charList. So X move forward 4 will become B. We can implement this logic by having index + key modulus by 26 (Line 13).  

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Answer:

50

var X gets passed into the rectangle function, which I assume would set the x and y coordinates to what the var's have already been set to.

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