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2 years ago

Write the expression using exponents.23 · y · y · y · y

Mathematics

1 answer:

Ostrovityanka [42]2 years ago

3 0

Answer:

Exponent: 23y^4

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The hypotenuse of the right triangle is 1 in. more than twice the longer leg. The length of the shorter leg is √10 in. Find the

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1 year ago

What is the sign of the product (–7)(–2)(–5)(1)?

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The product would be negative. Since there are three negative integers, the product would be negative. Two negatives make a positive, but another negative makes the end result negative.

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3 years ago

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If a/b < c/d with b > 0, d > 0, prove that a+c / b+d lies between the two fractions a/b and c/d .

Tems11 [23]

Divide through everything by b :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ab + \dfrac cb}{1 + \dfrac db}$

Since a/b < c/d, it follows that

$\dfrac{a+c}{b+d} < \dfrac{\dfrac cd+\dfrac cb}{1 + \dfrac db}$

Multiply through everything on the right side by b/d to get

$\dfrac{a+c}{b+d} < \dfrac{\dfrac{bc}{d^2}+\dfrac cd}{\dfrac bd+1} = \dfrac{\dfrac cd\left(\dfrac bd+1\right)}{\dfrac bd+1} = \dfrac cd$

and so (a + c)/(b + d) < c/d.

For the other side, you can do something similar and divide through everything by d :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ad + \dfrac cd}{\dfrac bd + 1}$

and a/b < c/d tells us that

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ad + \dfrac ab}{\dfrac bd + 1}$

Then

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ab + \dfrac{ad}{b^2}}{1 + \dfrac db} = \dfrac{\dfrac ab\left(1+\dfrac db\right)}{1 + \dfrac db} = \dfrac ab$

and so (a + c)/(b + d) > a/b.

Then together we get the desired inequality.

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3 years ago

W = p ( y -z ) Please solve this for z.

11111nata11111 [884]

w = p(y - z)

divide p on both sides

$\frac{w}{p} = y - z$

Subtract y on both sides

$\frac{w}{p} - y = -z$

Divide -1 on both sides

$-\frac{w}{p} +y=z$

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3 years ago

Pls help! Will give 100 points!

sdas [7]

Answer:

surely it's 200 marbles bc 2/4 is equal to 1/2 and if u then half 400 you get 200

Step-by-step explanation:

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2 years ago

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Write the expression using exponents.23 · y · y · y · y ​

Write the expression using exponents.23 · y · y · y · y