X^2 + 6x - 7 =
(x + 7)(x - 1)
<span>( 2x - 9 ) ( x + 6 )
( 2x ) ( x ) + ( 2x ) ( 6 ) + ( - 9 ) ( x ) + ( - 9 ) ( 6 )
2x² + 12x - 9x - 54
2x² + 3x - 54.</span>
The roots of the equation is x = 4.56 OR x = 0.44
<h3>Quadratic equation</h3>
From the question, we are to determine the roots of the given equation
The given equation is
x² -5x +2 = 0
Using the formula method,

In the given equation,
a = 1, b = -5, c = 2
Putting the values into the formula,



OR 
OR 
OR 
x = 4.56 OR x = 0.44
Hence, the roots of the equation is x = 4.56 OR x = 0.44
Learn more on Quadratic equation here: brainly.com/question/8649555
#SPJ1
Answer:
d
Step-by-step explanation:
Δ OPG is right with hypotenuse OG being the radius of the circle
Using Pythagoras' identity in the right triangle
OG² = OP² + PG²
[ PG = 11 , since OP is the perpendicular bisector of FG ]
OG² = 8² + 11² = 64 + 121 = 185
Δ OQS is right with hypotenuse OS being the radius
Using Pythagoras' identity
OS² = QS² + OQ² , that is
185 = 13² + x²
185 = 169 + x² ( subtract 169 from both sides )
16 = x² ( take the square root of both sides )
4 = x → d